Answer:
8
Step-by-step explanation:
a A + b A where A is a matrix and a and b are scalars
( a+b) A
3+5
= 8![\left[\begin{array}{cc}-1&2\\4&-5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5C4%26-5%5Cend%7Barray%7D%5Cright%5D)
Answer:
1by 20
Step-by-step explanation:
no of digit by no of sides
Answer:
Step-by-step explanation:
7(p-6)=8p-34
Distribute 7 into the parentheses on the Left Hand Side of the equation
7p-42=8p-34
get p together, so minus 7p on both sides
7p-7p-42=8p-7p-34
7p and -7p cancel out on L.H.S
-42=p-34
isolate p by adding 34 to both sides
-42+34=p-34+34
-34 and postitive 34 cancel out on the R.H.S
p=-8
Hope this helps! :)
C! Like terms refer to the variables that are the same, rather than the coefficients (the numbers).
Answer:
B the range, the x- and y-intercept
Step-by-step explanation:
the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).
but the range changes, as for the original function y could only have positive values - even for negative x.
the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.
the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.
the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.
the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.
the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)



