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Andrew [12]
3 years ago
15

Five percent of all vcrs manufactured by a large electronics company are defective. a quality control inspector randomly inspect

s groups of 10 vcrs from the production line. using the tables for the binomial probability distribution, what is the probability that exactly one of the vcrs is defective in any one group of 10 vcrs?
Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0
Binomial
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n=10)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (defective/normal)3. Probability is known and remains constant throughout the trials (p=5%)4. All trials are random and independent of the others (assumed from context)The number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Substituting values, p=0.05, n=10, X=exactly 1
for X=1 (defective out of n)
P(X=1)=C(10,1)0.05^1*(1-0.05)^(10-1)
=10!/(1!9!)*0.05*0.95^9
=10*0.05*0.0630249
=0.315125 (to 6 places of decimal)
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Find the real roots of the equation x^4-5x^2-36=0
Usimov [2.4K]
Treat x^4 as the square of p:  x^4 = p^2.

Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.

This factors nicely, to (p-9)(p+4) = 0.  Then p = 9 and p = -4.

Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.

Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
6 0
3 years ago
A collection of numerical information, such as the scores on a test, is referred to as simple random sampling.True / False.
Nimfa-mama [501]

Answer:

False. See explanation below.

Step-by-step explanation:

False

A simple random sample "is a subset of a statistical population in which each member of the subset has an equal probability of being chosen"

In other words that means in order to apply a random sampling we need to ensure that we have the same probability of inclusion for every possible element of the population of interest.

And for this case a collection of any numerical information is not referred as random sampling since we don't know if these scores are representative of the population of interest.

And we don't know if this information is obtained using any sampling frame or sampling methodology.  

8 0
3 years ago
An office supply company sells two types of fax
Phantasy [73]

14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.

To solve this problem, we would write a system of linear equations.

  • Let x represent the machine that cost $150
  • Let y represent the machine that cost $225

We can proceed to write our equations now.

x + y = 22...equation(i)\\150x + 225y = 3900...equation(ii)

From equation 1

x+ y = 22\\x = 22 - y...equation (iii)

<h3>The Value of Y</h3>

put equation (iii) into (ii)

150x + 225y =3900\\x = 22-y\\150(22-y)+225y=3900\\3300-150y+225y=3900\\3300+75y=3900\\75y=3900-3300\\75y=600\\75y/75=600/75\\y=8

<h3>The Value of X</h3>

Since we know the number of y, we can simply substitute it into equation (i) and solve.

x + y = 22\\x + 8 = 22\\x = 22-8\\x = 14

From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.

Learn more about system of equations here;

brainly.com/question/13729904

3 0
3 years ago
RSTUV - EABCD. Find AE.
larisa86 [58]

9514 1404 393

Answer:

  AE = 3

Step-by-step explanation:

First of all, we need to find corresponding sides that are defined in both figures. The table below shows the given values.

From the table, we can write the proportion ...

  EA/RS = BC/TU . . . corresponding sides are proportional

  EA/6 = 4/8 . . . . . . . substitute given lengths

  EA = 6(4/8) = 3

The length of AE is 3 units.

3 0
2 years ago
Find the indicated sum of each sequence S8 of -2,-13,-24,-35
valentina_108 [34]

Answer:

The sum of the arithmetic sequence is S_{8}=-324.

Step-by-step explanation:

A sequence is a set of numbers that are in order.

In an arithmetic sequence the difference between one term and the next is a constant.  In other words, we just add the same value each time infinitely.

If the first term of an arithmetic sequence is a_1 and the common difference is d, then the nth term of the sequence is given by:

                                                  a_{n}=a_{1}+(n-1)d

For the sequence

                                                -2,-13,-24,-35,...

The pattern is continued by adding -11 to the last number each time.

An arithmetic series is the sum of an arithmetic sequence.  We find the sum by adding the first, a_1 and last term, a_n, divide by 2 in order to get the mean of the two values and then multiply by the number of values, <em>n</em>

<em>                                                     </em>S_{n}=\frac{n}{2}(a_{1}+a_{n})<em />

The sum of the arithmetic sequence is

a_{8}=-2+(8-1)(-11)=-2-77=-79

S_{8}=\frac{8}{2}(-2-79})=4\left(-2-79\right)=4\left(-81\right)=-324

3 0
3 years ago
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