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3 years ago

If A, dollars are invested at annual interest rate r, compounded

Mathematics

1 answer:

frez [133]3 years ago

6 0

Answer:

$11,991.60

Step-by-step explanation:

An appropriate formula is ...

A = P(1 +r/n)^(nt)

where r is the annual rate, n is the number of time per year interest is compounded, and t is the number of year. P is the principal invested.

Filling in the given numbers, we have ...

A = $2000(1 +0.12/12)^(12·15) = $2000(1.01^180) ≈ $11,991.60

The account balance after 15 years will be $11,991.60.

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Solve x - 6x = 40 by factoring. What is<br> the solution?

marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0

3 years ago

Point w id located at (-2,3) on a coordinate plane. Point W is reflected over the x-axis to create point W" is then reflected ov

Anna11 [10]

Answer:

W'' = (2, -3)

Step-by-step explanation:

Reflection over the x-axis negates the y-coordinate and leaves the x-coordinate alone. The W becomes ...

... W' = (-2, -3)

Reflection over the y-axis negates the x-coordinate and leaves the y-coordinate alone. The W' becomes ...

... W'' = (2, -3)

5 0

2 years ago

Read 2 more answers

What is the answer of this problem -7/3(3x-2)=-21 ?

weeeeeb [17]

Answer:

= 11/3

Step-by-step explanation:

1. COMBINE MULTIPLIED TERMS INTO A SINGLE FRACTION

- 7/3 (3x-2)= -21

-7 (3x-2) = -21

-----------------------

2. DISTRIBUTE

-7( 3x- 2) ➗ 3 =-21

3. MULTIPLY ALL TERMS BY THE SAME VALUE TO ELIMINATE FRACTION DENOMINATORS

-21x + 14 ➗ 3 = 3 (-21)

4. CANCEL MULTIPLIED TERMS THAT ARE IN THE DENOMINATOR

3 ( -21x + 14) ➗ 3 (-21)

5. MULIPLY THE NUMBERS

-21x + 14 = 3(-21)

6. SUBTRACT 14 FROM BOTH SIDES OF THE EQUATION

-21x + 14 = -63

7. SIMPLIFY

-21x = - 77

8. DIVIDE BOTH SIDES OF THE EQUATION BY THE SAME TERM

-21x/-21 = -77/-21

9. SIMPLIFY

x = 11/3

3 0

3 years ago

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0

3 years ago

What is the distance covered by a train while slowing down from

alukav5142 [94]

Answer:

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6 $m/s^{2}$

Or uniform acceleration, a = - 1.6 $m/s^{2}$

<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

$v'^{2} = v^{2} + 2as$

$6^{2} = 20^{2} + 2(- 1.6)s$

$36 - 400 = - 3.6s$

$s = \frac{- 364}{- 3.6} = 113.75\ m$

5 0

3 years ago