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A study is conducted to investigate whether customer satisfaction is greater among computer companies that offer tech support ve
1 answer:
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Answer:
Step-by-step explanation:
Given
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From the question, the range is:
Range is calculated as:
From the box, we have:
So:
The box, becomes:
From the question:
--- interquartile range
This is calculated as:
is the median of the upper half while
is the median of the lower half.
So, we need to split the given boxes into two equal halves (7 each)
<u>Lower half:</u>
<u>Upper half</u>
<u></u><u></u>
The quartile is calculated by calculating the median for each of the above halves is calculated as:
Where N = 7
So, we have:
So,
= 4th item of the upper halves
= 4th item of the lower halves
From the upper halves
<u></u><u></u>
<u></u>
We have:
can not be determined from the lower halves because the 4th item is missing.
So, we make use of:
Where and
So:
So, the lower half becomes:
<u>Lower half:</u>
From this, the updated values of the box is:
From the question, the median is:
and
To calculate the median, we make use of:
This means that, the median is the average of the 7th and 8th items.
The 7th and 8th items are blanks.
However, from the question; the mode is:
Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:
The 8th item is calculated as thus:
Multiply through by 2
The updated values of the box is:
From the question.
Mean is calculated as:
So, we have:
Collect like terms
Multiply through by 14
This gives:
From the updated box,
We know that:
<em>The 2nd value can only be either 2 or 3</em>
<em>The 12th value can take any of the range 33 to 57</em>
Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:
i.e.
So, the complete box is: