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erma4kov [3.2K]
3 years ago
13

Determine the point that lies on the equation y = -5x - 3.

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

(4, -23)

Step-by-step explanation:

We are given;

  • The equation, y = -5x -3

We are needed to determine the point that lies on the equation;

  • We need to know that for a point to be lying on the equation it must satisfy the equation.
  • This means when we use the value of x in the equation we should get the exact value of y of the given point;
  • Therefore, in this case;

Point (4, -23)

Replacing x = 4 in the equation;

y = -5(4) - 3

 = -23

Therefore, the point lies on the equation as the point satisfies the equation

Thus, the required point is (4, -23)

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Solve 14^x+1=36<br> Round to the nearest ten-thousandth.
Umnica [9.8K]

Answer:

x = 1.3472 to the nearest ten thousandth.

Step-by-step explanation:

14^x + 1 = 36

14^x = 35

Taking logarithms:-

x ln 14 = ln 35

x = ln 35 / ln 14

= 1.3472.

6 0
3 years ago
What is six and eighty-seven thousandths
Kitty [74]

Answer:

6.087

Step-by-step explanation:

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7 0
3 years ago
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Simplify. Remove all perfect squares from inside the square root. V75 =​
scZoUnD [109]

Answer:

5√5

Step-by-step explanation:

You can rewrite √75 as √(25 * 5) and since 25 is a perfect square, you can find the square root and take that outside of the square root. √25 = 5, so √75 is equal to 5√5, and that cannot be simplified furthermore.

6 0
3 years ago
Laura buys four BDs at $14 each and six CDs at $12 each. What is her change from $120?
castortr0y [4]

BDs

4 \times 14 = 56

CDs

6 \times 12 = 72

Total

56 + 72 = 128

There is no change from $120 because she doesn't have enough money.

8 0
3 years ago
Multiply or divide as indicated. Leave your answer with no factors in the denominator. p⁻⁴q⁵r⁶/p⁻³qr⁻²
KIM [24]

Answer: \frac{q^4r^8}{p}

Step-by-step explanation:

By the Negative exponent rule, we know that:

a^{-1}=\frac{1}{a}

By the Quotient of powers property, we know that:

\frac{a^m}{a^n}=a^{(m-n)

And by the Product of powers property, we know that:

(a^m)(a^n)=a^{(m+n)}

Applying this properties, we get:

\frac{p^{-4}q^5r^6}{p^{-3}qr^{-2}}=\frac{p^3q^5r^6r^2}{p^4q}=\frac{q^4r^8}{p}

5 0
3 years ago
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