Determine the point that lies on the equation y = -5x - 3.

Mathematics

1 answer:

scZoUnD [109]3 years ago

8 0

Answer:

(4, -23)

Step-by-step explanation:

We are given;

The equation, y = -5x -3

We are needed to determine the point that lies on the equation;

We need to know that for a point to be lying on the equation it must satisfy the equation.
This means when we use the value of x in the equation we should get the exact value of y of the given point;

Therefore, in this case;

Point (4, -23)

Replacing x = 4 in the equation;

y = -5(4) - 3

= -23

Therefore, the point lies on the equation as the point satisfies the equation

Thus, the required point is (4, -23)

You might be interested in

Omar broke a cell sample into 8 batches, each

Nady [450]

Step-by-step explanation:

we have 8 equally "heavy" batches.

one weighs 3.9 × 10^-10 g

so, the total sample then weighed

8 × 3.9 × 10^-10 = 31.2 × 10^-10 = 3.12 × 10^-9 g

7 0

2 years ago

Can someone do 4, 5, 7 and 8 im failing math and avoiding a whooping

Valentin [98]

The answer to five is 75

4 0

3 years ago

Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). Pease show how!

mote1985 [20]

Check the picture below.

using a second for it, since it's a horizontal line, then say hmmm we'll use the y-intercept, or (0, 1), so the equation of a line that passes through (2,1) and (0,1)

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ 1}})\quad 
% (c,d)
&({{ 0}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-1}{0-2}\implies \cfrac{0}{-2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=0(x-2)$