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worty [1.4K]
3 years ago
13

I don’t understand what’s it asking me to do!! I have done this problem 12 times and I still don’t understand it. :(

Mathematics
1 answer:
pickupchik [31]3 years ago
4 0
Solve for x. so first u would subtract 25 from 25 and 298. 25 will be crossed out so now u are left with 13x<273. to solve that, divide 13 on both sides. 13 would be crossed or so now u are left with x<13. that means x can equal anything less than 13. idk about the rest, i think u can do it. :)
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Step-by-step explanation:

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1.5x + 1.5x + 0.75x - 3 + - 3 + - 1

3.75x + - 7

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Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in
nadezda [96]

Answer:

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

X \sim N(288,3.7)  

Where \mu=288 and \sigma=3.7

The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

Using this condition we can find the limits

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

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