G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Answer:
19
Step-by-step explanation:
just 19
Answer:
Domain is x and Range is y
Step-by-step explanation:
Domain-(16,-15,22,-1,-6)
Range-(5,-17,-16,-4,-14)
To find y you must recognize that 141+3y=180 . You know this since half of a circle is 180, and a line is basically half a circle if you arc from end point to end point.
You can then subtract 141 from both sides,
3y = 39
Then divide both sides by 3,
y=13
You would want to use 39° for 3y° since 3·13= 39.
A triangle can only contain 180°, so you would add 68 and 39 together and then subtract this from 180 to give you x.
68 + 39 + x = 180
107 + x = 180
x = 73
