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3 years ago

12

The graph shows the number of words Denise types in a given number of minutes. If Denise continues to type at the same pace, how

many words will she have typed in 5 minutes?

2 answers:

goldenfox [79]3 years ago

5 0

Ugh this is hard is this multiple

worty [1.4K]3 years ago

4 0

Answer: 250 words

Step-by-step explanation:

Equation: y= x+50

(Sorry if I’m wrong, I learned this in 6th grade)

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What is 1/7 As a decimal?<br><br> Give your answer rounded to 2 decimal places.

PIT_PIT [208]

Answer:

0.14

Step-by-step explanation:

1/7 = 0.1428571429.......

round to two decimal places so se look at the 4 which is the second decimal place, and then we see that the number to the right of it is less than 5 and therefore we round down to 4 and not 5.

:) hope this helps, please mark as brainliest!

4 0

3 years ago

The beginning balance in Cash was $3,500. Additional cash of $2,000 was received. Checks were written totaling $2,500. The cash

iragen [17]

3500+2000 = $5500
5500-2500 = $3000 so it would be 3000

6 0

3 years ago

Read 2 more answers

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$

Hence, the quotient is (x-2).

6 0

3 years ago

Read 2 more answers

Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t

schepotkina [342]

Answer:

(A) Set A is linearly independent and spans $R^3$ . Set is a basis for $R^3$ .

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors $A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)$ , we are to decide which of the given statements is true:

In Matrix $A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)$ , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. $R^3$ has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans $R^3$ .

Therefore Set A is linearly independent and spans $R^3$ . Thus it is basis for $R^3$ .

8 0

3 years ago

14/7x8-35/7x2 help me simplify using order of operations

zlopas [31]

4116 first answer 7 times 8 subtract 35.Second multiply by 14.Lastly solve 7 times 2 and multiply it by what you got multiplying 14.

3 0

3 years ago