The forward differences for this data is 1, 1, 1, 1, 1, 1 (since 10 - 9 = 1, 11 - 10 = 1, etc). Since we only need one iteration of differences, a linear polynomial will fit the data exactly.
The answer is actually D. The limit on the left side is computing the derivative at x = a. The right side value of 7 tells us that f ' (a) = 7
tan( tehta ) = 2/3
Sin( tetha ) = 2/√13
tan( tetha ) + Sin( tetha ) = 2/3 + 2/√13
= 2√13 + 6 / 3√13
Answer:
f = 5.12
Step-by-step explanation:
f(8)=0.8(8)^2
f(8)=6.4^2
f(8)=40.96
f(8)/8 = 40.96/8
f = 5.12
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