1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oxana [17]
2 years ago
5

Here is a rectangle ABCD. The length of the rectangle is increased by 10%. The width of the rectangle is increased by 5%. Find t

he percentage increased in the perimeter of tge rectangle.

Mathematics
1 answer:
sladkih [1.3K]2 years ago
6 0

Answer: Width would become 21 and length would become 33. Original perimeter is 100, increased perimeter is 108 which is a 7.69% increase

You might be interested in
A student measured the volume of an iron nail to be 0.880 cm3. She found its mass was 6.92grams. What is the density of iron?
Natali [406]

Answs,dv

Step-by-step explanation:

8 0
2 years ago
A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o
Novay_Z [31]
The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft


 
5 0
3 years ago
Someone please help i dont know how to solve for 6 and 7 <br> :(
Sphinxa [80]

If I remember correctly, the solutions are only on the solid line or in the shaded area? therefore Answers could be:

6.) (-3,0.5) (-4,0) (-2,0) (-2,-5) (-3,-5) (-4,-1) (-3,-1) (-2,-1)

7.) (-1,0) (-2,0) (-3,0) (0,-1) (-4,-1)

7 0
2 years ago
1) Solve ;
Rashid [163]

Answer:

x ≤ 7/2

Step-by-step explanation:

Expand brackets:                   3x - 15 ≤ x - 8

Subtract x from both sides:   2x - 15 ≤ -8

Add 15 to both sides:                    2x ≤ 7

Divide both sides by 2:                   x ≤ 7/2

3 0
2 years ago
Read 2 more answers
f(x) = 2<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex
loris [4]

Answer:

No answer is possible

Step-by-step explanation:

First, we can identify what the parabola looks like.

A parabola of form ax²+bx+c opens upward if a > 0 and downward if a < 0. The a is what the x² is multiplied by, and in this case, it is positive 2. Therefore, this parabola opens upward.

Next, the vertex of a parabola is equal to -b/(2a). Here, b (what x is multiplied by) is 1 and a =2, so -b/(2a) = -1/4 = -0.25.

This means that the parabola opens upward, and is going down until it reaches the vertex of x=-0.25 and up after that point. Graphing the function confirms this.

Given these, we can then solve for when the endpoints of the interval are reached and go from there.

The first endpoint in -2 ≤ f(x) ≤ 16 is f(x) = 2. Therefore, we can solve for f(x)=-2 by saying

2x²+x-4 = -2

add 2 to both sides to put everything on one side into a quadratic formula

2x²+x-2 = 0

To factor this, we first can identify, in ax²+bx+c, that a=2, b=1, and c=-2. We must find two values that add up to b=1 and multiply to c*a = -2  * 2 = -4. As (2,-2), (4,-1), and (-1,4) are the only integer values that multiply to -4, this will not work. We must apply the quadratic formula, so

x= (-b ± √(b²-4ac))/(2a)

x = (-1 ± √(1-(-4*2*2)))/(2*2)

= (-1 ± √(1+16))/4

= (-1 ± √17) / 4

when f(x) = -2

Next, we can solve for when f(x) = 16

2x²+x-4 = 16

subtract 16 from both sides to make this a quadratic equation

2x²+x-20 = 0

To factor, we must find two values that multiply to -40 and add up to 1. Nothing seems to work here in terms of whole numbers, so we can apply the quadratic formula, so

x = (-1 ± √(1-(-20*2*4)))/(2*2)

= (-1 ± √(1+160))/4

= (-1 ± √161)/4

Our two values of f(x) = -2 are (-1 ± √17) / 4 and our two values of f(x) = 16 are (-1 ± √161)/4 . Our vertex is at x=-0.25, so all values less than that are going down and all values greater than that are going up. We can notice that

(-1 - √17)/4 ≈ -1.3 and (-1-√161)/4 ≈ -3.4 are less than that value, while (-1+√17)/4 ≈ 0.8 and (-1+√161)/4 ≈ 2.9 are greater than that value. This means that when −2 ≤ f(x) ≤ 16 , we have two ranges -- from -3.4 to -1.3 and from 0.8 to 2.9 . Between -1.3 and 0.8, the function goes down then up, with all values less than f(x)=-2. Below -3.4 and above 2.9, all values are greater than f(x) = 16. One thing we can notice is that both ranges have a difference of approximately 2.1 between its high and low x values. The question asks for a value of a where a ≤ x ≤ a+3. As the difference between the high and low values are only 2.1, it would be impossible to have a range of greater than that.

7 0
2 years ago
Other questions:
  • Two rhombuses with the same side lengths are always congruent ?
    6·1 answer
  • Pablo makes $23 each day raking leaves. About how much money does Pablo make in one week?
    10·1 answer
  • Simplify to create an equivalent expression<br><br> -y minus -3(-3y+5)
    13·1 answer
  • Write the quadratic equation whose roots are 6 and -2, and whose leading coefficient is 4,
    10·2 answers
  • Answer this pls !!!.... and thanx !
    15·2 answers
  • THE THING ON THE TOP IS y=4/3x-4<br> Y=2/3x-6
    15·1 answer
  • The circumference of a circle is divided into twelve equal arcs. The measure of each arc is
    6·1 answer
  • Simplify<br> -1 – 8i<br> —3— 51
    13·1 answer
  • Write the slope intercept form of a line containing the y - intercept (0, -3) with a slope of –1.
    15·1 answer
  • Pls help just look at the picture's
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!