Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
Answer:
2n+7
Step-by-step explanation:
find the difference
and see the difference from the 2 Times table to the original sequence
and write it as an equation for this sequence
Answer:

Step-by-step explanation:
remember: tan(theta) = opposite/adjacent
First, distribute the 12
156-168-15=16+4+x
-27=20+x
-47=x