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Vlad1618 [11]
3 years ago
10

Given the following function, find h(3). h(t) = t2 − t + 7

Mathematics
1 answer:
g100num [7]3 years ago
7 0

Answer:

Step-by-step explanation:

h(t) = t² - t + 7

h(3) = 3² - 3 + 7 = 9 - 3 + 7 = <em>13</em>

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Answer:

12

Step-by-step explanation:

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2 years ago
Out of 22 players in a team, 10 of them have an average height of 1.50m while another 10 have an average height of 1.48m. The re
Sonja [21]

Answer:

1.5 meters

Step-by-step explanation:

We know that the sum of all of the data in a set = average * number of data.

Therefore, the sum of the first 10 is 1.5 * 10 = 15 meters, the sum of the second 10 is 1.48 * 10 = 14.8 meters and the sum of the last 2 is 1.6 * 2 = 3.2 meters for a total of 15 + 14.8 + 3.2 = 33 meters. This means that the mean is 33 / 22 = 1.5 meters.

6 0
3 years ago
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Laura wants to cover the floor of her rectangular bedroom with carpet. Laura's bedroom is 15 feet in
Kryger [21]

Area = Length x width.

Area of room = 15 x 24 = 360 square feet.

Now multiply the square feet by the cost:

360 x 5 = $1800

It will cost $1,800

8 0
3 years ago
Please help me with number 4!
Mariulka [41]

Answer:

x = 20√2 and y = 20√3.

or x = 28.28 and y = 34.64 to the nearest hundredths.

Step-by-step explanation:

Take the 2 'inside' triangles. They are similar.

So we have  x / (60-40) = 40 / x

x/ 20 = 40 /x

x^2 = 800

x = √800

x = 20√2

y = √(800 + 20^2)

= √(1200)

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8 0
3 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15. Check all of the following you includ
zepelin [54]

The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

7 0
2 years ago
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