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Artyom0805 [142]
3 years ago
7

7 watermelons cost $8.96.Which equation would help determine the cost of the 5 watermelons? Into two fractions with a expontnet

Mathematics
1 answer:
mestny [16]3 years ago
4 0

Answer:

hola CTM

Step-by-step explanation:

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At what time since leaving their flowers do Bee 1 and Bee 2 have the same distance remaining?
GrogVix [38]

By reading the given graph with the two linear functions, we want to see at which time do the two bees have the same distance remaining. We will see that the correct option is B, 6 minutes.

So, in the graph, we have distance remaining on the vertical axis and time on the horizontal axis.

We also have two lines, each one describing the distance of each bee as a function of time.

We want to see at which time do the two bees have the same distance remaining, thus, we need to see when the lines intersect (this means that for the same time, the two bees have the same distance remaining).

In the graph, we can see that the intersection happens at the time of 6 minutes, thus the correct option is B; 6 minutes.

If you want to learn more about linear function's graphs, you can read:

brainly.com/question/4025726

6 0
3 years ago
Lola walks 4/10 mile to her friends house. then she walks 5/10 mile to the store. how far does she wall in all?
Masteriza [31]
We know that <span>Lola walks 4/10 mile to her friends house. then she walks 5/10 mile to the store. 

To solve the problem we have to use addition. 

4/10 + 5/10 = 9/10 

Lola walks 9/10 miles. </span>
8 0
3 years ago
Read 2 more answers
Question 1 of
AnnyKZ [126]

Answer:

5L/2 < 100

Step-by-step explanation:

Let's get started!

Let :

⇒ Length = L

⇒ Width = L/4

It mentions the perimeter must be less than 100 inches.

Perimeter Formula :

<u><em>Perimeter (Rectangle) = 2(Length + Width)</em></u>

Then, the inequality formed will be :

⇒ 2 (L + L/4) < 100

⇒ 2 (5L/4) < 100

⇒ 10L/4 < 100

⇒ 5L/2 < 100

3 0
2 years ago
Read 2 more answers
Joan needs to estimate the size of her bedroom so that she can buy enough paint to cover the walls. Two of the walls measure 2.8
labwork [276]

The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.

The measurement of two of the walls is 2.86 metres and 3.16 metre

Area of the two walls = 2(length x breadth)

Area = 2(2.86 x 3.16) = 18.0752 m²

The measurement of the other two walls is 2.86 metres and 3.42 metres

Area of the two walls = 2(length × breadth)

Area = 2(2.86 × 3.42) = 19.5624 m²

Total area = 18.0752 + 19.5624 = 37.6376 m²

If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be

No. of cans = Total area/Area covered by one can of paint

No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)

3 0
1 year ago
How many outcomes are there if you roll two dice with side sides
Valentin [98]
36 different outcomes.

6 x 6 = 36

Each side of dice 1 could have a counter match of 6 possibilities x 6
8 0
3 years ago
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