What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?
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If x = 4 is the Only Solution of the Equation x² + bx + 16 = 0
Then the Value x = 4 should satisfy the Given Equation
⇒ (4)² + b(4) + 16 = 0
⇒ 16 + 4b + 16 = 0
⇒ 4b + 32 = 0
⇒ 4b = -32
⇒ b = -8
The function is divided in 2 parts:
For x<0, the function is
, which is a linear function, and its graph is a line.
For x≥0, the function is
, which is a quadratic function, and its graph is a parabola.
Note that y=x is the line containing the points (0, 0), (1, 1), (5, 5) etc, that is, it is the line passing through the origin, with an inclination of 45° with the positive x-axis.
The parabola is the parabola 
reflected with respect to the x-axis. It contains points like (0, 0), (-1, 1), (2, -4) etc...
The 2 graphs, with domain all real numbers, are shown in the first picture.
The second picture is the graph of the function described in our problem. We use the first picture, but restrict the domains.
That is, we delete the part of the line corresponding to x≥0, and the part of the parabola corresponding to x<0.
For x<0, the function is
For x≥0, the function is
Note that y=x is the line containing the points (0, 0), (1, 1), (5, 5) etc, that is, it is the line passing through the origin, with an inclination of 45° with the positive x-axis.
The parabola
The 2 graphs, with domain all real numbers, are shown in the first picture.
The second picture is the graph of the function described in our problem. We use the first picture, but restrict the domains.
That is, we delete the part of the line corresponding to x≥0, and the part of the parabola corresponding to x<0.