Answer:
Hello Sir/ Mam
YOUR REQUIRED ANSWER IS 18.6%
Variables defined in the question:
H - Home - Games
W - Winning Games
Now, given:
P(H0.62 PW)0.22
P(W\mid H)=0.30
Required : Of all the games, percentage of games that were at home wins.
Hence, required :
P(W\cap H)
Now, we know that:
P(W\mid H)=\frac{P(W\cap H)}{P(H)}
0.3=\frac{P(W\cap H)}{0.62}
Hence,
P(W\cap H)=0.3*0.62=0.186=18.6\%
I hope this solves your doubt.
Feel free to comment if you still have any query.
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Wyzant
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tbh i be wasting m time and ur tiem no kap
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