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Natalka [10]
3 years ago
11

Cassidy wrote the linear equation y=5x+4. Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes th

rough (8,–2). If her new equation is in the form y=5x+b, what is the value of b?
Mathematics
1 answer:
melisa1 [442]3 years ago
7 0
Since it's parallel the scale is kept and you just plug in the point in order to get the y-intercept.
y=5x+b
(-2) =5 (8) + b
-2 =40 +b
b = -42
 
So the final equation would be y=5x-42
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