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2 years ago

10

A scale model of a car is 10 in. long. The actual car is 15 ft long. What is the scale of the model?

2 answers:

gtnhenbr [62]2 years ago

7 0

Answer:

1 in. : 18 in.

Step-by-step explanation:

First convert the 15 ft to inches. 12x15 = 180

So for every 10 inches in length of the model, there are 180 inches in the actual car. 10 in. : 180 in.

10/180 can be simplified to 1/18.

For every inch in the model, there are 18 inches in the actual car.

1 in. : 18 in.

nikklg [1K]2 years ago

5 0

Oh this question is kinda tricky. At first glance it’s 1 : 1.5 but notice the units. The model car is 10 inches long and the actual car is 15 feet long.

I think you know where to go from there, but 15 feet * 12 inches = 180 inches.

10 : 180 simplifies to 1 : 18 inches

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kherson [118]

Answer:

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Step-by-step explanation:

To find out how many people had it initially, plug 0 in for x (implying 0 days later.)

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C= 1*0

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To find out how many people had it after 2 days, plug 2 in for x. (implying 2 days later.)

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3 years ago

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trapecia [35]

Answer:

<em>y = - cos ( </em> $\frac{3}{4}$ <em> x + </em> $\frac{\pi }{4}$ <em> ) </em>

Step-by-step explanation:

y = A cos ( Bx + C) + D

Vertical shift D = 0

A = - 1

Compression / Stretching B

Period of given function is $\frac{8\pi }{3}$

Period of cos x is 2π

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Horizontal shift is C ÷ B

Horizontal shift of given function is $\frac{\pi }{3}$

$\frac{\pi }{3}$ = C ÷ $\frac{3}{4}$ ⇒ C = $\frac{\pi }{4}$

So, the equation of given function is

<em>y = - cos ( </em> $\frac{3}{4}$ <em> x + </em> $\frac{\pi }{4}$ <em> ) </em>

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2 years ago

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Ganezh [65]

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Step-by-step explanation:

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3 years ago

The perimeter of a square is 60 inches. Find the area.

Marianna [84]

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Step-by-step explanation:

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2 years ago

Factor 5v^2 - 23v - 10

AfilCa [17]

Answer:

$(5v + 2)(v - 5)$

Step-by-step explanation:

Hello!

The expression is written in the form of $ax^2 + bx + c$

Let's factor by grouping:

$ac = -50$

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

$5v^2 - 23v - 10$
$5v^2 - 25v + 2v - 10$
$5v(v - 5) +2(v -5 )$
$(5v + 2)(v - 5)$

The factored expression is $(5v + 2)(v - 5)$

7 0

1 year ago