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arsen [322]
3 years ago
15

A basketball player makes 70% of his free throws the random numbers below represent 20 trials for a simulation let the numbers 0

to 6 represent a made free throw and let 7 to 9 represent a missed free throw use this simulation to estimate the probability that the player makes both free throws. (5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4) (6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)
Mathematics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

Step-by-step explanation:

Nesterboy [21]3 years ago
6 0

Answer:

40%

Step-by-step explanation:

Given the result of the simulation below:

(5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4)

(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)

n(S)=20

  • The numbers 0 to 6 represent a made free throw .
  • The numbers 7 to 9 represent a missed free throw.
  • Therefore, any result containing 7 to 9 does not satisfy our requirement that the player makes both throws.

Let Event A be the event that the player made both throws

The pairs in which the player made both throws are:

(5,5) (0,6) (0,4) (1,4) (5,3)  (3,5)  (2,1) (0,6)

n(A)=8

Therefore:

P(A)=\frac{n(A)}{n(S)}=\frac{8}{20}=0.4\\

The probability that the player made both throws is 40%.

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A spherical ball has a radius of 4 inches. What is the volume of this sphere, to the
stealth61 [152]

Answer:

V = 267.9 in^3

Step-by-step explanation:

V = 4/3 * (pi) * r^3

V = 4/3 * 3.14 * 4^3

V = 4/3 * 3.14 * 64

V = 256/3 * 3.14

V = 803.84/3

7 0
2 years ago
At a fabric store, the probability that a customer buys thread is 0.15. The probability that a customer buys a needle given that
Sveta_85 [38]

Answer:

The correct statement is:

C. Buying a needle and buying a thread are dependent events.

Explanation:

The first statement is incorrect because the given events are dependent on each other because the probability that a customer buys a needle given that the customer buys thread is 0.25.

The second statement is incorrect because we cannot say all those who buy a thread also buy a needle.

The fourth statement is incorrect because the probability that a customer buys a needle and thread is 0.25 \times 0.15=0.0375



8 0
3 years ago
Simplify. 16 + 24 ÷ 4 • 2 - 3. <br><br>A. -2<br>B. - 10<br>C. - 11<br>D. - 25​
Bess [88]

Answer:

25

Step-by-step explanation:

16+24÷4•2-3

16+6•2-3

16+12-3

28-3

25

5 0
3 years ago
Read 2 more answers
18 necklaces made in 3 hours. so how many are made in 3 hours?
Westkost [7]

Answer: there are 18 necklaces made in 3 hours

Step-by-step explanation:

6 0
2 years ago
According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildif
suter [353]

Answer:

The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.

Step-by-step explanation:

We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.

If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.

The standard deviation of the sample is equal to:

\sigma_s=\sqrt{\frac{\pi(1-\pi)}{N}}=\sqrt{\frac{0.8*0.2}{500}}=0.018

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

z=\frac{p-\pi}{\sigma}=\frac{0.79-0.80}{0.018} =\frac{-0.01}{0.018} = -0.55\\\\z=\frac{p-\pi}{\sigma}=\frac{0.81-0.80}{0.018} =\frac{0.01}{0.018} = 0.55

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

P(0.79

3 0
3 years ago
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