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OlgaM077 [116]
3 years ago
13

Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?

Mathematics
2 answers:
tiny-mole [99]3 years ago
5 0

Answer:

its B

Step-by-step explanation:

Odyssey ware

aleksandrvk [35]3 years ago
3 0
To solve this problem, we must simplify the the equation:
<span>Here is the base equation -2m - 5m - 8 = 3 + (-7) + m (Add all like terms):

</span>#1 -2m - 5m - 8 = 3 + (-7) + m (Property of Addition)<span>
#2 -7m - 8 = -4 + m (Most Simplified Equation)

The answer your would be the 2nd one. </span>-7m - 8 = m - 4
<span>
If I helped you out, please give me a gold crown. :)

</span>
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3x=9<br> solve for x<br> show work
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Answer:

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Step-by-step explanation:

3x=9

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3 years ago
1).Calculate T, when sample mean is 120, population mean is 100, standard deviation is 20 and smaple size is 10 using levels of
Sonbull [250]

Answer:

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=120 represent the sample mean  

s=20 represent the standard deviation for the sample

n=10 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 100, the system of hypothesis would be:  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{120-100}{\frac{20}{\sqrt{10}}}=3.16  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=10-1=9

Conclusion

Since is a tao tailed test the p value would be:  

p_v =2*P(t_{9}>3.16)=0.012  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and the true mean is significantly different from 100 at 5% of significance.  

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kAnswer: There is a mistake into this i think

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