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beks73 [17]
3 years ago
14

What’s The values of 30%of81

Mathematics
1 answer:
krek1111 [17]3 years ago
7 0

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{30\% of 81}}{\left(\cfrac{30}{100} \right)81}\implies 24.3

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<em>9/-1</em>

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Because you do what’s in parentheses first which is (6+3)

You get the answer 9

Then you do 4-5 which will lead to going into negative numbers and the answer will be -1

So 9/-1 or Nine divided by negative one

5 0
3 years ago
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

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ln e as an inverse simplifies to 1.

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We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
Ben is taking a typing class, and the following line graph represents the number of words per minute he was able to type each we
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During week 2, he could type 15 words per minute, at his fourth week, he could type 30. So 30-15=15. He could type 15 words faster on week 4 than he could at week 2.
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Step-by-step explanation:

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Step-by-step explanation:

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