Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
nd BD = 6. What is the area of kite ABCD? 15 square units 30 square units 45 square units 60 square units
1 answer:
Answer:
![30 u^{2}](https://tex.z-dn.net/?f=30%20u%5E%7B2%7D)
Step-by-step explanation:
The computation of the area of kite ABCD is shown below:
Given data
AC = 10 ;
BD = 6
As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal
Now the area of quadrilateral when the diagonals are given
So, it is
![\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20area%20of%20kite%20%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20d_%7B1%7D%20d_%7B2%7D)
where,
![d_{1}=10\ and\ d_{2}=6](https://tex.z-dn.net/?f=d_%7B1%7D%3D10%5C%20and%5C%20d_%7B2%7D%3D6)
So, the area of the quadrilateral is
![=\frac{1}{2}(10)(6)\\\\=30 u^{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%2810%29%286%29%5C%5C%5C%5C%3D30%20u%5E%7B2%7D)
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Answer:y=Mx+b
Step-by-step explanation:
140 + 6x = 462 - 10x
Hope I helped
Have a great day
Then it would be 9/10 don't you know anything times 1 is its self even fractions
20/100 =x/6
20 multiply 6 =120
120 divide by 100 =1.2