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storchak [24]
3 years ago
10

Which pair or pairs of polygons are congruent ?

Mathematics
1 answer:
german3 years ago
7 0

Answer:

E. 1, 2, 3, and 4

Step-by-step explanation:

Well all them are equal,

both rectangles in part 2 has a 3cm^2 area.

Both red and green in part 4 has 2 squares and 1 triangle or half of a square.

Both of part 3 have all the same shapes in them.

Same with part 1 both shapes have same area and perimeter.

Thus, answer choices E. 1,2,3, and 4 is correct.

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Express 5/7 as a decimal. (Round to the nearest thousandths place)
Georgia [21]

Answer:

rounding to the thousandths place, the answer is 0.714

Step-by-step explanation:

This can easily be looked up on google

5 0
3 years ago
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Plz I need help as soon as you see this... and I need the work so I understand it plz!​
poizon [28]

Answer:

8. Obtuse

11. Obtuse

Step-by-step explanation:

c^2 = a^2 + b^2

for 8, it's 6 squared plus 9 squared, which is 117. now, 15 squared is 225. 225 is bigger than 117, which makes it obtuse. if the two results equaled each other, it would be a right triangle. if the 2 smaller numbers when squared were bigger than the hypotenuse squared, then it would be acute

4 0
3 years ago
Choose the most appropriate name for the function described below. The postage required to mail a box depends on its weight
Stells [14]

Answer:

Postage(weight) or p(w)

Step-by-step explanation:


6 0
4 years ago
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Please helpp quick! i have no idea what the answer is
aleksley [76]

Answer:

C

Step-by-step explanation:

point-slope equation is y-y1=m(x-x1)

y1=2

x1=6

m=(-5/7)

so the equation is y-2=-5/7(x-6)

hope this helps :3

5 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl
kicyunya [14]
Hello,

u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \  r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \  a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\


8 0
4 years ago
Read 2 more answers
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