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liraira [26]
3 years ago
13

Please help, would be greatly appreciated

Mathematics
1 answer:
velikii [3]3 years ago
6 0
1. We first simplify both sides of the equation, factoring the parentheses and adding like numbers:
5x - (x + 3) =  \frac{1}{3} (9x + 18) - 5 \\ 5x - x - 3 = 3x + 6 - 5 \\ 4x - 3 = 3x + 1
Then, we move all the Xs to one side and all the numbers to the other by subtracting 3x from both sides and adding 3 to both sides:
4x - 3 = 3x + 1 \\ 4x - 3x = 1 + 3 \\ x  = 4
We get x = 4.


2. First, we simplify:5(3x + 9) - 2x = 15x - 2(x - 5) \\ 15x + 45 - 2x = 15x - 2x + 10 \\ 13x + 45 = 13x + 10
Then, we try to move the Xs to one side, but we get 13x - 13x, which equals 0x. This problem is impossible, as it states 45 = 10.
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Write 5/10 in three equivalent forms
krek1111 [17]

equivalent fractions are fractions which have the same value.

equivalent fractions all have the same simplified form

we can write equivalent fractions by multiplying both numerator and denominator by the same number. We can also write equivalent fractions by dividing both numerator and denominator by the same number

so 5/10

we can get the equivalent fractions by multiplying by a common number

when we multiply by 2

\frac{5}{10}* 2= \frac{5*2}{10*2} = \frac{10}{20}

when we multiply by 3

\frac{5}{10}* 3 = \frac{5*3}{10*3} = \frac{15}{30}

when we multiply by 4

\frac{5}{10} *4 = \frac{5*4}{10*4}  = \frac{20}{40}

the three equivalent fractions are

10/20 , 15/30, 20/40

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Find all zeros of function and write the polynomial as a product of linear factorsX^3-x^2+9x-9
mart [117]

Answer:

\large\boxed{x=1\ \vee\ x=-3i\ \vee\ x=3i}

Step-by-step explanation:

\text{The zeros:}\\\\x^3-x^2+9x-9=0\\\\x^2(x-1)+9(x-1)=0\\\\(x-1)(x^2+9)=0\iff x-1=0\ \vee\ x^2+9=0\\\\x-1=0\qquad\text{add 1 to both sides}\\x-1+1=0+1\\\boxed{x=1}\\\\x^2+9=0\qquad\text{subtract 9 from both sides}\\x^2=-9

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Answer:

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Step-by-step explanation:

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Hope this helped:))
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