Help ! not sure what do do
1 answer:
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Answer:
2.5%
Step-by-step explanation:
It is given that:
lifespans of seals in a particular zoo are normally distributed. The average seal lives 13.8 years and the standard deviation is 3.2 years.
We want to use the empirical rule to estimate the probability of a seal living longer than 7.4
Let's calculate the z-score of 7.4 using
According to empirical rule, 95% of the distribution is within 2 standard deviations, i.e (-2 to 2)
So from (-2 to 0), we would have 47.5%
Since we are looking for the area to the left of -2.00 we subtract this from 50%
to get 2.5%