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postnew [5]
3 years ago
7

You spin the spinner for candy land. There are 4 colors on the spinner that have equal likelihoods of occurring. These colors ar

e red, blue, green, and yellow. What's the chance of spinning green? Record your answer as a simplified fraction using "/" as your fraction key.
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

1/4

Step-by-step explanation:

If you have four colors on the spinner and you want to land on the green spot and there is 1/4 chances

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Solve the equation for x in terms of c
Dovator [93]

solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}

\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

2cx=\frac{29}{4}

\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
8 0
3 years ago
If (x+1)/x=6,then x=?​
Salsk061 [2.6K]

Answer:(x+1)/x=6,then x=1/5 or 0.2

Step-by-step explanation:

8 0
3 years ago
Which point below is a solution to the equation y = 2x + 3?
Anastasy [175]

Answer:

C (37, 77)

Step-by-step explanation:

<h3>Option A:</h3>

291=2(145)+3\\\\291=290+3\\\\\boxed{291\neq 293}

Option A is not a solution.

<h3>Option B:</h3>

163=2(78)+3\\\\163=156+3\\\\\boxed{163\neq 159}

Option B is not a solution.

<h3>Option C:</h3>

77=2(37)+3\\\\77=74+3\\\\\boxed{77=77}

Option C is a solution.

Hope this helps.

6 0
3 years ago
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barxatty [35]
Add them together and divide it by 2 since there are two numbers
125.75+(-10.25)=115.5
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the mean is 57.75
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3 years ago
James, Priya and slobhan work in a grocery store. James makes $7.00 per hour. Priya makes 20% more than James, and slobhan makes
Mars2501 [29]
7.20 is the correct answer to the problem.
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