Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle KOM
In the triangle KOM
we have


Applying the law of cosines







step 2
Find the measure of the arc KM
we know that
----> by central angle
we have

so

step 3
Find the measure of angle KLM
we know that
The inscribed angle is half that of the arc comprising
![m\angle KLM=\frac{1}{2}[arc\ KM]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20KM%5D)
we have

substitute
![m\angle KLM=\frac{1}{2}[106.26^o]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5B106.26%5Eo%5D)

P(7,6), Q(1,6), R(4,2)
We have PQ parallel to the x axis. We'll call that the base,
b = 7 - 1 = 6
The altitude is then the y difference h = 6 - 2 = 4
The area is 
Answer: 12 square units
In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:
(7,6), (1,6), (4,2)
(1,6), (4,2), (7,6)
The area is then half the absolute value of the sum of the cross products:

C. Both can be used to withdraw money from ATMs.
Answer: C. x = 6; m∠XOY = 18
Step-by-step:
We see that ZOW and WOX are supplementary, meaning the sum of their angles equal 180.
We also know that WOY is a right angle and equals 90.
Now we can solve
180-108 = 72
90 - 72 = 18
XOY = 18
Because 3x = 18, we know that x = 18 by dividing 18 by 3
46+19+54= 119, so the answer is 119