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miss Akunina [59]
2 years ago
6

What is the domain of the function?

Mathematics
1 answer:
Nostrana [21]2 years ago
6 0

Answer:

option c........... .

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Complete the passage to describe velocity vs time graphs.A velocity vs time graph is a graph that shows the relationship between
Fiesta28 [93]
1)Time is plotted on the x-axis in seconds
2)Velocity of the object is plotted on the y-axis in meters per second
4 0
3 years ago
Liz earns a salary of $2,100 per month, plus a commission of 5% of her sales. She wants to earn at least $2,400 this month. How
Nookie1986 [14]
Hello! She earns a salary of $2,100, which is the fixed amount each month, plus 5% commission on her sales. To find out the amount of sales that will help her reach her goal, set up the inequality like this:

2,100 + 0.05x ≥ 2,400

We set it up like this, because $2,100 is the one-time price per month, and she earns 5% of her sales as commission. Plus, the key words "at least" means the inequality sign is greater than or equal to (≥)

How to solve this:

First off, subtract 2,100 from both sides, when you do, you get 0.05x ≥ 300. Now, divide each side by 0.05 to isolate the "x". 300/0.05 is 6,000. Let's check this. 6,000 * 5% (0.05) is 300. There. x = 6,000. Liz will need to sell $6,000 worth of items this month in order to meet her goal.
7 0
3 years ago
In a video game, players form teams and work together to earn as many points as possible for their team. Each team can have betw
stealth61 [152]

Answer:

1. 2 ≤ n ≤ 4

2. 4 * 20

3. T < 80

4. (2 * 4) + (4 * 3)

5. 16 ≤ P ≤ 32

Note: The quantities described are as follows:

1) the allowable number of players on a team  

2) the number of points,  , Han's team earns in one round if every player earns a perfect score  

3) the number of points,  , Han's team earns in one round if no players earn a perfect score  

4) the number of players,  , in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each

5) the possible number of players in a game with eight teams

Step-by-step explanation:

1. Let the number of players be n

Since each team can have between 2 and 4 players

n ≥ 2 or 2 ≤ n, and n ≤ 2

Therefore, the allowable number of players on a team   is given by 2 ≤ n ≤ 4

2) There are four players in Han's team and a perfect score is 20

Therefore, the number of points Han's team earns in one round if every player earns a perfect score   is given by 4 * 20

3) There are four players in Han's team

Total score if each player in Han's team earns a perfect score is 4 * 20 = 80

Let the total score of Han's team be T

Therefore, the number of points, Han's team earns in one round if no players earn a perfect score   is given by T < 80

4) If two team have 4 players, it is given by 2 * 4

If the rest four teams have 3 players each, it is given by 4 * 3

Therefore, the number of players in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each  is given by (2 * 4) + (4 * 3)

5) Let the possible number of players in a game with be P

Maximum number of players in eight teams = 4 * 8 = 32

Minimum number of players in eight teams = 2 * 8 = 16

P ≤ 32 and P ≥ 16 or 16 ≤P

Therefore, the possible number of players in a game with eight teams  is given by 16 ≤ P ≤ 32

4 0
3 years ago
Write a word problem that can be solved by multiplying a whole number and a fraction. Include the solution.
adelina 88 [10]

Answer:

Sheila had 24 cupcakes, she gave 1/3 of them to Caleb. How many cupcakes did she give to Caleb?

Step-by-step explanation:

24 x 1/3 = 8

She gave 8 cupcakes to Caleb.

8 0
2 years ago
Y''+y'+y=0, y(0)=1, y'(0)=0
mars1129 [50]

Answer:

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form ay''+by'+cy=0.

Given: y''+y'+y=0

Let y=e^{rt} be it's solution.

We get,

\left ( r^2+r+1 \right )e^{rt}=0

Since e^{rt}\neq 0, r^2+r+1=0

{ we know that for equation ax^2+bx+c=0, roots are of form x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} }

We get,

y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}

For two complex roots r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta, the general solution is of form y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )

i.e y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

Applying conditions y(0)=1 on e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right ), c_1=1

So, equation becomes y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

On differentiating with respect to t, we get

y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )

Applying condition: y'(0)=0, we get 0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}

Therefore,

y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )

3 0
3 years ago
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