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nikitadnepr [17]
3 years ago
14

To division problems must be interpreted correctly to answer real life problems.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0
I agree with you because life is math.math is all around us
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Write the fact family for 5,8,and 40
Juli2301 [7.4K]
A fact family is basically just different equations with the same numbers getting the same/different numbers as answers you might say... 
this will make more sense: 
5x8=40
8x5=40
40/8=5
40/5=8
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3 years ago
45 centimeters is equivalent to how many inches?
Fiesta28 [93]

It is equivalent to 17.7165 inches.

5 0
3 years ago
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What is the period of the sinusoidal function
rodikova [14]

Answer:

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.

Step-by-step explanation:

3 0
2 years ago
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Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re
kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read 13\frac{3}{4} pages in \frac{1}{4} of an hour.

Therefore, pages read by Zander in 1 hour = \frac{\text{Total pages read}}{\text{Total time taken}}

= \frac{13\frac{3}{4}}{\frac{1}{4}}

= \frac{55}{4}\times \frac{4}{1}

= 55 pages per hour

Sydney read 43\frac{1}{3} pages in \frac{2}{3} of an hours.

Pages read by Sydney in 1 hour = \frac{43\frac{1}{3}}{\frac{2}{3} }

= \frac{130}{3}\times \frac{3}{2}

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

4 0
3 years ago
Please help The perimeter of a rectangular shape electronic keyboard is 14 ft. Its width is 3 ft longer than its depth
kipiarov [429]

Answer:

Width = 6ft Area = 54 sq ft

Step-by-step explanation:

First, re-read the problem until you understand it and can put it into your own words.  I re-wrote it like this:  "Find the area of a rectangle by first finding the length (L) and the width (W)."   [note that I added "find L and W," but that is how I'm going to solve the problem;  I could also have said that we will need the formulas, P=2L+2W and A=LW, but you knew that already, right?).

 

Translate the problem:

 "The length of a rectangle is 3 ft longer than its width"      means

         L                             =    3             +         W                 (eq1)

 "the perimeter of the rectangle is 30 ft"     means

            P                                = 30                      (eq2)

 

So, now the math is easy, just find L and W so we can compute the area:

     P = 30 = 2L + 2W                         (eq3; from eq2 and the formula for P)

          30 = 2(3+W)  +  2W              (use eq1 to substitute for L)

          30 = 6 + 2W   + 2W              (distribute)

           30 = 6 + 4W                       (collect terms)

            24 = 4W                        (subtract 6 from both sides)

            6 ft = W                         (divide both sides by 4)

 

Use the easiest equation (either eq1 or else eq3) to find L:

          L = 3 + W        (eq1)

          L = 3 + 6

          L = 9 ft

What is the area (A)?

          A = L*W

          A = (9 ft)*(6 ft)

          A = 54 sq ft

3 0
3 years ago
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