Coordinate of image triangle is M'(-6,-2),N'(-1,7) and P'(3,4)
Step-by-step explanation:
The given triangle MNP has coordinates of M(-2,6), N(7,1), and P(4,-3)
In matrix form, It can be written as :
![\left[\begin{array}{ccc}-2&7&4\\6&1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%267%264%5C%5C6%261%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Triangle has to rotate by angle of 90 degree at origin.
Counterclockwise Rotation matrix is given by :
![\left[\begin{array}{ccc}cos\theta&-sin\theta\\sin\theta&cos\theta\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dcos%5Ctheta%26-sin%5Ctheta%5C%5Csin%5Ctheta%26cos%5Ctheta%5Cend%7Barray%7D%5Cright%5D)
For 
![\left[\begin{array}{ccc}0&-1&\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Image of triangle MNP will be
=
![\left[\begin{array}{ccc}-2&7&4\\6&1&-3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%267%264%5C%5C6%261%26-3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=![\left[\begin{array}{ccc}-6&-1&3\\-2&7&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%26-1%263%5C%5C-2%267%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Thus,
The coordinate of image triangle is M(-6,-2),N(-1,7) and P(3,4)