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3 years ago

The surface area of a typical classroom floor is closest to______.

2 answers:

4 0

Answer would be C. Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field. Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side. Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth. Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there. I hope my explanations were detailed and easy to understand. :)

Trava [24]3 years ago

3 0

The correct answer to this question is letter "C. 10 m^2." The surface area of a typical classroom floor is closest to 10 meters squared. Choice A is too big for a classroom. Choice B is very very small to be used as a classroom. Choice D is quite not that enough.

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What could be a reason for isolating a variable in a literal equation

svlad2 [7]

A literal equation is an equation where variables represent known values. Literal equations allow use to represent things like distance, time, interest, and slope as variables in an equation. You isolate one variable because your goal is to solve for just one variable with respect to others.

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3 years ago

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

sp2606 [1]

Answer by JKismyhusbandbae: $76.50

Explanation: Substitute 3 for m and simplify.

Work: (Attached in Picture)

7 0

3 years ago

Read 2 more answers

Hey does any body know how i can approximate 13 like this had this homework but it got late on me.

Illusion [34]

Answer:

(see attachment)

To approximate the square root of 13:

Working from the top down...

Enter the number you are trying to approximate in the top box: $\boxed{\sf \sqrt{13}}$

Find the perfect squares directly below and above 13.

Perfect squares: 1, 4, 9, 16, 25, 36, ...

Therefore, the perfect squares below and above 13 are: 9 and 16

Enter these with square root signs in the next two boxes: $\boxed{\sf \sqrt{9}}$ and $\boxed{\sf \sqrt{16}}$

Carry out the operation and enter $\boxed{\sf 3}$ and $\boxed{\sf 4}$ in the next two boxes.

Enter the number you are trying to square root (13) in the top left box, the perfect square above it (16) in the box below, then the perfect square below it (9) in the two boxes to the right of these. Carry out the subtractions and place the numbers in the boxes to the right.

$\dfrac{\boxed{\sf 13}-\boxed{\sf 9}}{\boxed{\sf 16}-\boxed{\sf 9}}=\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}$

Now enter the number you are trying to square root (13) under the square root sign. Place the square root of the perfect square below it (3) in the box to the right. Copy the fraction from above (4/7). Finally, enter this mixed number into a calculator and round to the nearest hundredth.

$\sf \sqrt{13}=\boxed{\sf3}\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}=\boxed{\sf3.57}$

7 0

2 years ago

A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.

S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

$x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)$

where:

$(x_A,y_A)=(-7,3)$ are the coordinates of point A

$(x_B,y_B)=(-1,0)$ are the coordinates of point B

$(x_C,y_C)$ are the coordinates of point C

Solving the equation for $x_C$ ,

$x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1$

Solving the equation for $y_C$ ,

$y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1$

So, the coordinates of point C are

$C(-1,1)$

Learn more about how to divide segments:

brainly.com/question/3269852

brainly.com/question/11280112

#LearnwithBrainly

4 0

3 years ago

Plz help I don't know much about what this question is asking me

Ann [662]

Answer:

Step-by-step explanation:

You can see that the only difference between the three questions is the charge of the electrons. Electrons are negatively charged and so the answer is just B

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3 years ago

Read 2 more answers