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nikitadnepr [17]
2 years ago
13

The surface area of a typical classroom floor is closest to______.

Mathematics
2 answers:
avanturin [10]2 years ago
4 0
Answer would be C. Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field. Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side. Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth. Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there. I hope my explanations were detailed and easy to understand. :)
Trava [24]2 years ago
3 0
The correct answer to this question is letter "C. 10 m^2." The surface area of a typical classroom floor is closest to 10 meters squared. Choice A is too big for a classroom. Choice B is very very small to be used as a classroom. Choice D is quite not that enough. 
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4 0
2 years ago
How to substitute 3x+3y=-3 and y=5x-1?
schepotkina [342]
Since y = 5x-1, we can fill it into 3x + 3y = -3. First, let's look at relating to a simpler equation. Let's say that x + y = 9 and y = 3 + 5. Now, we can fill it in to get that x + (3 + 5) = 9. Now, we know that 3+5 is 8, so x + 8 = 9. Now, x = 1. Likewise, we can do the same. For 3x + 3y = -3, all we need to do is to switch the y in 3x + 3y = -3 with 5x - 1. So it would become 3x + 3(5x - 1) = -3. Now we distribute to get 3x + 15x - 3 = -3. Now add three to both sides to get 3x + 15x = 0. Now simplify to get 18x = 0. Now we know that x = 0. Now fill x into y = 5x - 1. So y = 5(0) - 1. Now we know that y = -1.

To check fill in the answer to 3x + 3y = -3.
3(0) + 3(-1) = -3
 0 + (-3) = -3
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-3 = -3
Now that our check is completed we now know that x is 0 and y is -1.
7 0
3 years ago
In a statistics class of 13 sophomores, 12 juniors, and 8 seniors, 5 of whom are male sophomores, 6 of whom are female juniors,
8_murik_8 [283]

Answer:

\frac{20}{33}

Step-by-step explanation:

We are given that

Sophomores=13

Juniors=12

Seniors=8

Male sophomores=5

Female sophomores=6

Male seniors=4

We have to find the probability of randomly selecting a junior or  a senior.

Total persons=13+12+8=33

Let A=Seniors

B=Juniors

Probability,P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of cases}

Using the formula of probability

P(A)=\frac{8}{33}

P(B)=\frac{12}{33}

A\cap B=0

P(A\cap B)=0

P(A\cup B)=P(A)+P(B)-P(A\cap B)

P(A\cup B)=\frac{8}{33}+\frac{12}{33}

P(A\cup B)=\frac{8+12}{33}=\frac{20}{33}

Hence, the probability of selecting a junior or senior=\frac{20}{33}

3 0
3 years ago
What is the amount of discount on a $475 TV if the discount is 15%
ASHA 777 [7]
$475*0.15=$71.25 discount
8 0
3 years ago
Find the angle θ between u = <7, –2> and v = <–1, 2>.
Dmitry_Shevchenko [17]

The angle between two vectors is:

CosФ = u - v / Magnitude(u) x magnitude(v)

Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)

Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)

u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11

cosФ = -11 / sqrt(53) x sqrt(5)

cosФ = -11sqrt265) / 265

Ф =cos^-1(-11sqrt265) / 265)

Ф=132.51 degrees.

7 0
3 years ago
Read 2 more answers
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