you will divide 36 by 1 and multiply 2 on both sides which makes 72 by 2 so 2into 1 is 2 and 2 into 36 is 72
Answer:
The atomic mass of element X is 69.724 amu
Explanation:
Given data:
Atomic mass of element X= ?
Percent abundance of X-68.926 = 60.10%
percent abundance of X-70.925 = 39.90%
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (68.926×60.10)+(70.925×39.90) /100
Average atomic mass = 4142.4526 +2829.9075/ 100
Average atomic mass = 6972.3601 / 100
Average atomic mass = 69.724 amu.
The atomic mass of element X is 69.724 amu.
Answer:
Your question is not complete, but use this answer as a guide for your solution.
Question: A chemistry student weighs out 0.112g of acetic acid (HCH₃CO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1600 <em>M</em> NaOH solution. Calculate the volume of solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.
Answer: Volume of NaOH is 11.6 mL
Explanation:
The reaction of acetic acid with NaOH is as follows:
CH3COOH + NaOH -----> CH3COONa + H2O
M1V1 = M2V2
Here M1 V1 are molarity and volume of acetic acid.
M2, V2 are molarity and volume of NaOH.
Number of moles of acetic acid:
0.112 g CH3COOH × (1 mol / 60.05 g) = 0.001865 mol
Molarity = moles of solute / Liters of solution
Molarity = 0.001865 mol / 0.250 L = 0.00746 M
Hence,
M1 = 0.00746 M
V1 = 250 mL
M2 = 0.160 M
V2 = ?
V2 = M1V1 / M2
V2 = 0.00746 M × 250 mL / 0.160 M
V2 = 11.6 mL
Hence the volume of NaOH is 11.6 mL
Answer:
The presence of nitrogen in the organic compound is detected by fusing organic compounds with sodium metal to give sodium cyanide (NaCN) soluble in water. This is converted into sodium ferrocyanide by the addition of sufficient quantities of ferrous sulphate.
Explanation:
It is what I found online.
Answer: 2.3 moles
Explanation:
Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms
So if 1 mole of Aluminum = 6.02 x 10^23 atoms
Then, Z moles = 1.4 x 10^24 atoms
To get the value of Z, we cross multiply:
1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)
1.4 x 10^24 atoms = Z x (6.02 x 10^23)
Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)
Z =2.3 moles
Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.