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3 years ago

NEED HELP NOW!!!!

Mathematics

1 answer:

Dovator [93]3 years ago

5 0

Answer:

f(x) = -3x --->#6

f(x) = |x-1|+3 --->#5

f(x) = √(x+3) --->#3

1/2x² --->#1

f(x) = (x+1)²-3 --->#4

4|x|--->#2

Step-by-step explanation:

Recall for transformations:

Adding a number outside the function moves it up
Subtracting a number outside the function moves it down
Adding inside the function moves it to the left
Subtracting inside the function moves it to the right
Multiplying to the function by a number less than 1 compresses
Multiplying to a function by a number greater than 1 stretched it
Multiplying by a negative flips the graph

f(x) = -3x

This is multiplication by a number greater than 1 and a negative so this stretches and flip. This is #6, a reflection.

f(x) = |x-1|+3

Subtraction inside the function shifts it to the right 1 and addition outside shifts it up 3. This is #5.

f(x) = √(x+3)

Addition inside the function shifts it to the left 3. This is #3

1/2x²

Multiplication by 1/2 which is less than 1 compresses it. This is #1.

f(x) = (x+1)²-3

Addition inside the function shifts the function to the left once. This is #4.

4|x|

Multiplying by 4, a number greater than 1, stretches it. This is #2.

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Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loy

Paladinen [302]

Answer:

See Explanation and attachments

Step-by-step explanation:

Given

See question for data

Solving (a):

The scale used is an ordinal scale.

Ordinals scale uses hierarchy arrangement and the data can be arranged as:

$EARLY ->> ON-TIME ->> LATE ->> LOST$

The variable of the delivery performance is qualitative because it is non-numerical

Solving (b): Frequency table

From the table, we have:

$On - Time = 57$ $Early = 19$ $Late = 9$ $Lost = 2$

So, the frequency distribution table is:

$\begin{array}{cc}{Performance}&{Frequency}&{On-Time}&{57}&{Early}&{19}&{Late}&{9} & {Loss} & {2} & {Total} & {87}\end{array}$

Solving (c): Frequency table.

To do this, we add another column (Relative Frequency) to the above table.

The relative frequency is calculated as:

$Relative\ Frequency = \frac{Frequency}{Total}$

So, we have:

$On - Time = \frac{57}{87} = 0.656$ $Early = \frac{19}{87} = 0.218$

$Late = \frac{9}{87} = 0.103$ $Lost = \frac{2}{87} = 0.023$

So, the frequency distribution table is:

$\begin{array}{ccc}{Performance}&{Frequency}&{Relative\ Frequency} & {On-Time}&{57}&{0.656}&{Early}&{19}&{0.218} & {Late}&{9} & {0.103} & {Loss} & {2} & {0.023} & {Total} & {87}&{1}\end{array}$

Solving (d & e): See attachment 1 for bar chart & attachment 2 for pie chart

Solving (f):

From the question, we understand that the object is to return 99% early or on time and never to lose a package.

The analysis is as follows:

Early and On-Time (ET) packages

$ET = \frac{Early + On-Time}{Total} * 100\%$

$ET = \frac{57 + 19}{87} * 100\%$

$ET = \frac{76}{87} * 100\%$

$ET = \frac{7600}{87} \%$

$ET = 87.4 \%$

Lost packages

$Lost = \frac{Lost}{Total} * 100\%$

$Lost = \frac{2}{87} * 100\%$

$Lost = \frac{200}{87} \%$

$Lost = 2.30\%$

<em>From the above analysis, we can see that 87.4% of the packages were delivered early enough and 2.30% were lost. </em>

<em>The fraction of packages delivered early can be improved and the fraction of lost packages can be reduced by exploring the chances of taking alternative routes when possible. </em>

3 0

3 years ago

Find x in the triangle below. Round your answer to the nearest tenth.

jonny [76]

Answer:

Step-by-step explanation:

Remark

x is opposite the 90 degree angle. It is the hypotenuse.
13 makes up the 57 degree angle. It is the side adjacent.
The adjacent side and the hypotenuse define the cos(theta).

Formula

cos(theta) = adjacent side / hypotenuse

Givens

Theta = 57 degrees

Hypotenuse = x

Side adjacent = 13

Solution

Cos(57) = 13 / x Multiply both sides by x
x*cos(57) = 13 Divide by cos(theta)
x = 13/cos(57)
x = 13 / cos(57)
cos(57) = 0.5446
x = 13/ 0.5446
x = 23.87

6 0

3 years ago

The base of a cube is parallel to the horizon. If the cube is cut by a plane to form a cross section, under what circumstance wo

djverab [1.8K]

Answer:

A. when the plane passes through a pair of vertices that do not share a common face

Step-by-step explanation:

The cross section will be a parallelogram if two pairs of opposite faces are intersected. Having the plane contain the space diagonal, but no other vertices, is one way to ensure a (non-rectangular) parallelogram.

The only vertices not sharing a common face are the ones at opposite ends of a space diagonal. If the plane intersects both of those, it will contain the space diagonal.

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3 years ago

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babymother [125]

Answer:

was there supposed to be an attachment??

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3 years ago

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yulyashka [42]

5. you have to put it in a formula with sin
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4 years ago