Answer:
144 i multiplied 12x12=144
Step-by-step explanation:
Answer:
Simplifying
x2 + -4y2 = 25
Solving
x2 + -4y2 = 25
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4y2' to each side of the equation.
x2 + -4y2 + 4y2 = 25 + 4y2
Combine like terms: -4y2 + 4y2 = 0
x2 + 0 = 25 + 4y2
x2 = 25 + 4y2
Simplifying
x2 = 25 + 4y2
Reorder the terms:
-25 + x2 + -4y2 = 25 + 4y2 + -25 + -4y2
Reorder the terms:
-25 + x2 + -4y2 = 25 + -25 + 4y2 + -4y2
Combine like terms: 25 + -25 = 0
-25 + x2 + -4y2 = 0 + 4y2 + -4y2
-25 + x2 + -4y2 = 4y2 + -4y2
Combine like terms: 4y2 + -4y2 = 0
-25 + x2 + -4y2 = 0
The solution to this equation could not be determined.
Step-by-step sorry if im wrong
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
