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AveGali [126]
3 years ago
11

Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value u

sed to test a null hypothesis.
​α = 0.08; H1 is μ ≠ 3.24


a. ±1.75


b. 1.75


c. ±1.41


d. 1.41
Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

The critical z value used to test a null hypothesis is ±1.75.

Step-by-step explanation:

We are given that the data has a normal distribution and the number of observations is greater than fifty.

Also, the hypothesis given to us is;

<u>Null Hypothesis</u>, H_0 : \mu = 3.24

<u>Alternate Hypothesis</u>, H_1 : \mu\neq 3.24

This means that our test is two-tailed because in the alternate hypothesis we are concerned with mean value is less than or greater than 3.24.

Also, level of significance (α) = 0.08

Now, for two-tailed test level of significance becomes =  \frac{\alpha}{2} =\frac{0.08}{2} = 0.04

So, in the z-table the critical value of x at 4% significance level is given as 1.75.

Since, this is two-tailed test so the critical z value used to test a null hypothesis would be ±1.75.

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Answer:

Step-by-step explanation:

The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :

Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.

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Answer:

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Step-by-step explanation:

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Remark

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