Catherine bought 7 candy bars and 4 soft drinks from the concession

lozanna [386]

-13m = -377
m= -377/-13
m=29
the negatives cancel out. so just do 377/13 which equals 29

5 0

2 years ago

the five performers who will present their comedy acts this weekend at a comedy club how many different ways are there to schedu

wlad13 [49]

First day 1 in morning after noon and night next day one in morning and night

8 0

3 years ago

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If (x^2−1)/(x+1) = 3x + 5, then x + 3 = (A) -3 (B) -2 (C) 0 (D) 2 (E) 4

sineoko [7]

The answer is C) 0
Because math

4 0

2 years ago

Write a number or expression in each blank space to create true equations.

Rina8888 [55]

Answer:

$7(3+5)=7(3)+7(5)\\15-10=5(3-2)$

Step-by-step explanation:

Both expressions are examples of the distributive property, which basically says "if I have this many groups of some size and that many groups of the same size, I've got this + that groups of that size altogether."

To give an example, if I've got 3 groups of 5 and 2 groups of 5, I've got 3 + 2 = 5 groups of 5 in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.

Mathematically, we'd capture that last example with the equation

$5(3)+5(2)=5(3+2)$ . We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: $7(3+5)=7(3)+7(5)$ .

This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: $4(3)-4(1)=4(3-1)=4(2)$ . When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as 3 groups of 5 and 10 is the same as 2 groups of 5. Using the distributive property, we could write this as $15-10=3(5)-2(5)=5(3-2)$ , so we can say that $15-10=5(3-2)$ .

4 0

3 years ago

There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o

Anastaziya [24]

P(B/A) is $\frac{5}{9}$ in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

P(B|A) is called the "Conditional Probability" of B given A
Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

replacement

- That means red is already occurred when green is happened,

so it is a "Conditional Probability" of green given red

P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

the first draw

∴ P(A) = P(red)

∵ P(red) = $\frac{3}{10}$

∴ P(A) = $\frac{3}{10}$

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = $\frac{5}{9}$

∴ P(B) = $\frac{5}{9}$

- Find P( A and B)

∴ P(A and B) = ( $\frac{3}{10}$ ) . ( $\frac{5}{9}$ )

∴ P(A and B) = $\frac{15}{90}$

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = $\frac{1}{6}$

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = $\frac{\frac{1}{6}}{\frac{3}{10}}$

- Simplify the fraction

∵ $\frac{1}{6}$ ÷ $\frac{3}{10}$ = $\frac{1}{6}$ × $\frac{10}{3}$ = $\frac{10}{18}$

- Divide up and down by 2

∴ P(B/A) = $\frac{5}{9}$

P(B/A) is $\frac{5}{9}$ in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

7 0

2 years ago

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