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Ivahew [28]
2 years ago
15

Let p: A shape is a triangle.

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
7 0

Answer:

q -> p

Step-by-step explanation:

Given:

p: shape is a triangle

q: shape has 4 sides

= p -> q

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Fiona divided 3x2+5x-3 by 3x+2. The expression represents the remainder over the divisor.
Lera25 [3.4K]

Answer:

-5

Step-by-step explanation:

Shown in the attachment.

The remainder when 3x^2 +5x -3 is divided by 3x+2 is -5

4 0
4 years ago
Use factoring to solve the quadratic equation. 2x^2=5X+3
prohojiy [21]
Move everything to one side
Equation
2x^2 - 5x -3 = 0
Sq rt means square root or radical sign
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2a
- (-5) +/- Sq rt (-5)^2 - 4(2)(-3)
2 (2)
5 +/- Sq rt 25 + 24
4
Sq rt 29 = 5.38
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4 0
3 years ago
The picture below shows a box sliding down a ramp:
AURORKA [14]

Answer: Option 2

Step-by-step explanation:

\sin 65^{\circ}=\frac{12}{AC}\\\\AC=\frac{12}{\sin 65^{\circ}}\\\\\boxed{AC=12 \text{ cosec }65^{\circ}}

4 0
2 years ago
Simplify the algebraic expression:<br><br> 5 + 3(2y - 4) - 11y
Iteru [2.4K]

5 + 6  − 1 2 − 1 1  -11y 5+6y−12−11y − 7 + 6  − 1 1  

− 7 + 6  − 1 1   −7+6y−11y − 7 − 5  

− 7 − 5  −7−5y − 5  − 7

Solution: −5y−7

3 0
3 years ago
Read 2 more answers
B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,
Nadusha1986 [10]

Answer:

\huge{ \fbox{ \sf{Rs \: 40000}}}

Step-by-step explanation:

\sf{Let \: CP \: ( \: cost \: price) \: be \: x}

\sf{Loss \: \% \:  = 5  \% \: }

\sf{Selling \: price = CP \:  -  \: loss \: \% \: of \: CP}

\mapsto{ \sf  x -  \frac{5}{100}  \times x}

\mapsto{ \sf{x -  \frac{x}{20} }}

\mapsto{ \sf{  \frac{x \times 20 - x}{20} }}

\mapsto{ \sf{ \frac{20x - x}{20}}}

\mapsto{ \sf{ \frac{19x}{20}}}

Now, Finding the New selling price

\sf{New \: SP \: ( \: selling \: price)} =  \frac{19x}{20}  + 5200

\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}

\mapsto{ \sf{ \frac{19x + 10400}{20}}}

Finally, finding the Cost price :

We have, Profit % = 8 %

\sf{Cost \: price = Selling \: price \:  -  \: P\% \: of \: CP}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  - 8\% \: of \: x}}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{8x}{100} }}

\mapsto{ \sf{x =  \frac{19x + 104000}{20}  -  \frac{2x}{25} }}

\mapsto{ \sf{x =  \frac{5(19x + 104000) - 2x \times 4}{100} }}

\mapsto{ \sf{x =  \frac{95x + 520000 - 8x}{100} }}

\mapsto{ \sf{x =  \frac{87x + 520000}{100}}}

\mapsto{ \sf{100x = 87x + 520000}} \:  \: ( \sf{Cross \: multiplication}

\mapsto{ \sf{100x - 87x = 520000}}

\mapsto{ \sf{13x = 520000}}

\mapsto{ \sf{x =  \frac{520000}{13}}}

\mapsto{ \boxed {\sf{x = 40000}}}

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
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