<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
45 or multiples of 45 around the centre of octagon
Step-by-step explanation:
Given that ABCDEFGH is a regular octagon. i.e. it has 8 sides.
Since regular ocagon, all interior angles would be equal.
Sum of all interior angles of octagon = 2(8)-4 right angles
= 12 right angles
Hence each angle = 12(90)/8 = 135 degrees
Thus the octagon when rotated will take the same shape if vertices interchange also due to the property that all sides and angles are equal
Since each angle is 135 imagine an octagon with one vertex at origin O, and adjacent vertex B on x axis. OB has to be coincident with BC the next side or the previous side to get it mapped onto itself
The centre will be at the middle with each side subtending an angle of 45 degrees.
Hence if rotation is done around the centre with 45 degrees we will get octagon mapped onto itself.
45, 90, 135 thus multiples of 45
Step-by-step explanation:
9(x+1) = 25+x
open the bracket
9x + 9 = 25+x
collect like terms
9x-x = 25-9
8x = 16
x = 2
