What are the minimum, first quartile, median, third quartile and maximum of the data set 3,5,7,8,12,13,14,18,21
Wittaler [7]
Answer:
3, 7, 12, 14, 21
Step-by-step explanation:
3 is the minimum value of the data set.
The median is 12. (it is in the middle of 3 and 12 if you look at the question)
The first quartile is 7 (if you count, it is equidistant from either end)
the third quartile is 14. (it is in the middle of 12 and 21 if you look at the question)
21 is the maximum value of the data set.
Answer: 3 is minimum, 7 is first quartile, 12 is median, 14 is third quartile, and 21 is maximum.
Answer:
864x^2 + 102x + 24559
Step-by-step explanation:
Add the correct terms that correspond to the placement.
4x = -60 - 19y
-7x = -48 - 19y
Subtract the bottom equation from the top:
4x + 7x = -60 + 48 - 19y + 19y
Simplify:
11x = -12 -0y
11x = -12
Divide both sides by 11:
11x/11 = -12/11
Simplify:
x = -12/11
Then plug in x to solve for y:
4(-12/11) = -60 - 19y
Simplify:
-48/11 = -60 - 19y
Add 60 to both sides (keep in mind 60 = 660/11):
-48/11 + 660/11 = -60 + 60 - 19y
Simplify:
612/11 = 0 - 19y
612/11 = -19y
Divide both sides by -19 (keep in mind that dividing by -19 is the same as multiplying by -1/19):
612/11 • -1/19 = -19y/-19
Simplify:
-612/209 = y
y = -612/209
So, the answer is: (-12/11, -612/209)
Plug in x = 7. Then use the order of operations (PEMDAS) to simplify
y = 11 - 5*x
y = 11 - 5*7 .... x has been replaced with 7 (since x = 7 is given)
y = 11 - 35
y = -24
According to the empirical rule, approximately 68% of data fall within 1 standard deviation of the mean.