Basically, the closer they fit to the imaginary line of best fit, the higher they are
the closer the dots are to the imaginary line, te higher the number
D looks the closest together so that is first
A is a little farther apart
C is farther
B is farthers
DACB is order
The event "Atleast once" is the complement of event "None".
So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.
At Morning, the probability that Marvin does not teleport = 2/3
Likewise, the probability tha Marvin does not teleport during evening is also 2/3.
Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.
So, the probability that Marvin does not teleport during the day = 
Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.
Probability that Marvin teleports atleast once during the day = 
Answer:
x = 8
Step-by-step explanation:
This problem can be completed in 2 ways. Both are acceptable.
Option 1:This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.

The area of one of the triangles is half the base times the height.

The other triangle must have that area too.

The area is 56 square centimeters.
Option 2:We can use the area formula for the trapezoid.

Where

is the length of the shorter base
and

is the length of the longer base
and

is the height.
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.


Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.
Let x be the number of dimes
and y be the number of quarters
Total number of coins = 12
So number of dimes + number of quarters = total number of coins
x + y = 12 ---------> equation 1
We know, 1 Quarter = 25 cents, 1 Dime = 10 cents, total cents = 196
y quarters = 25y cents , x dimes = 10x cents
x dimes + y quarters = 195 cents
10x + 25y = 195 -----------> equation 2
Now solve both equations
x + y =12, we solve for y by subtracting x on both sides
y = 12-x
Now substitute y in second equation
10x + 25(12-x) = 195
10x + 300 -25x = 195 (combine like terms)
-15x + 300 = 195 (subtract 300 on both sides)
-15x = -105 ( divide by -15)
x=7
y= 12-x
y=12-7 = 5
The number of dimes = 7
Number of quarters = 5