Linear equation worksheet how to graph

Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

6 0

3 years ago

after eating 25 percent of the pretzels, Sonya had 42 left. how many pretzel did Sonya have originally?

Shtirlitz [24]

Answer:

56

Step-by-step explanation:

she ate 25% so she is left with 75%

you want to find that 25% so you do 75÷25=3

42÷3=14

25×4=100

14×4=56

she had 56 pretzels

7 0

3 years ago

A car rental agency Advertise renting a car for $24.95 per day and $.33 per mile is Kevin rent the car for today how many whole

pychu [463]

Answer:

Kevin can drive 681 miles.

Step-by-step explanation:

In order to find the amount that he can drive in one day and only pay $250, we have to write an equation for the cost. Using x as the miles he drive, we can express the equation as:

y = .33x + 24.95

Now, we can plug in 250 for y.

250 = .33x + 24.95

225.05 = .33x

681.97 = x

Since we are looking for only whole miles, we have to round down to 681.

6 0

3 years ago

Fei Yen's dog eats 8 ounces of dog food each day.Fei Yen's bought a 28 pound bag of dog food.How many 8 ounce servings are in a

joja [24]

Answer:

56

Step-by-step explanation:

Recall that 1 lb = 16 oz, meaning that 1/2 lb = 8 oz.

Thus, we need only divide 28 lb by 1/2 lb to determine the number of 8 oz servings are contained in a 28 lb bag of dog food:

28 lb

--------------------- = 56 8-oz servings

1/2 lb/ serving

8 0

3 years ago

The number of bagels sold daily for two bakeries is shown in the table:

ivann1987 [24]

Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.

<h3>What centers of distribution should be used?</h3>

The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.

The data is said to be symmetric when the mean and median are equal or very close.

Bakery A mean:

= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8

= 49

Bakery A median is 49.5

Bakery B mean:

= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8

= 39.5

Bakery B median is 44.

This shows that Bakery A data is symmetric so the best center of distribution to use is mean.

Bakery B is not symmetric so the center of distribution to use is median.

Find out more on symmetric data at brainly.com/question/7130507

#SPJ1

8 0

2 years ago