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noname [10]
3 years ago
7

Four polynomials are shown below:

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0

Answer:

Polynomial D

Step-by-step explanation:

D. 3x3 − 5 + 2x5 + x + 2x2


max2010maxim [7]3 years ago
6 0
The degree of a polynomial is the value of the highest exponent a variable is raised to (i.e., the degree of the equation y=x^{2} is 2, since the highest exponent of a variable is 2. 

If we apply this concept to your list of polynomials, we see that polynomial A and polynomial D both have x^{5} terms, so they are both fifth-degree polynomials. However, your answer must also be a trinomial (a polynomial with three terms.) If we look at polynomials A and D, we see that only polynomial A has three terms, so that must be the answer!

Let me know if you have any questions :)
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Multiply: 5 • (-3)
slamgirl [31]

Answer:

-15

Step-by-step explanation:

We can factor out a 1 from -3 to get 5\cdot(-3)=5\cdot-1\cdot3=-1(5\cdot3).

We know from simple arithmetic that 5\cdot3=5+5+5=10+5=15.

So, our answer is -1(15)=\boxed{-15}

6 0
3 years ago
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Find the distance between the points with coordinates (5, 7) and (-3, 1)
Bess [88]
You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.

Now plug in your numbers.

This gives you root(7-1)^2+(5-(-3))^2.

Simplify to root(6)^2+(8)^2. Simplify again to root36+64.

Simplify one more time to root 100. now solve.

Your answer is 10.
7 0
3 years ago
What is the integer closest to the square root of 17
Alex Ar [27]

Answer:

4

Step-by-step explanation:

\sqrt{16} = 4

7 0
3 years ago
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równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma
Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0
2 years ago
Can someone help????
Mandarinka [93]

Answer: my fingers are broken

Step-by-step explanation:

3 0
2 years ago
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