Answer:
Polonium: <em>Number</em><em> </em><em>of</em><em> </em><em>protons</em><em> </em><em>=</em><em> </em><em>8</em><em>2</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Number</em><em> </em><em>of</em><em> </em><em>neutrons</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>6</em>
Sodium: <em>Number</em><em> </em><em>of</em><em> </em><em>protons</em><em> </em><em>=</em><em> </em><em>1</em><em>1</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Number</em><em> </em><em>of</em><em> </em><em>neut</em><em>rons</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em>
The equation for the reaction between NaOH and AlCl₃ is as follows;
3NaOH + AlCl₃ ---> 3NaCl + Al(OH)₃
the stoichiometry of NaOH : AlCl₃ is 3:1
3 moles of NaOH reacts with 1 mol of AlCl₃ to produce 1 mol of Al(OH)₃
the number of AlCl₃ moles reacted - 6.5 mol
molar mass of NaOH -(23 +16 +1) = 40 g/mol
the number of NaOH moles reacted = 57.0 g / 40 g/mol
NaOH moles = 1.425 mol
either NaOH or AlCl₃ is in excess and other is the limiting reactant.
limiting reactant is the reactant whose number of moles are fully consumed during the reaction. the reactant that is in excess will have leftover moles that are remaining after the reaction.
If AlCl₃ is the limiting reactant, number of NaOH moles would be thrice the amount of AlCl₃ present,
then number of NaOH moles that should be present - 6.5 * 3 = 19.5 mol
however there are only 1.425 mol of NaOH present, therefore AlCl₃ is in excess.
Then NaOH is the limiting reactant,
the amount of products formed depends on the amount of the limiting reactant present.
stoichiometry of NaOH : Al(OH)₃ is 3:1
the number of Al(OH)₃ moles produced = number of NaOH moles reacted / 3
number of Al(OH)₃ moles are - 1.425 mol /3 = 0.475 mol
molar mass of Al(OH)₃ = (27 +3*16 + 3*1) = 78 g/mol
mass of Al(OH)₃ produced = 78 g/mol * 0.475 mol = 37.05 g
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
43.63g of C
Answer:
B.) 6
Explanation:
Attached below is the Lewis structure of PCl₃ . Since phosphorus (P) has 5 valence electrons and chlorine (Cl) has 7 valence electrons, there should be 26 valence electrons (5 + 7(3) = 26) in the Lewis structure.
Bonding electrons are the electrons present in the chemical bonds between two atoms.
There are 2 electrons shared in every single bond. Within PCl₃, there are 3 single bonds. As such, there are 6 bonding electrons in the Lewis structure of PCl₃.
5HNO₃ + 3P + 2H₂O = 3H₃PO₄ + 5NO
N⁺⁵ + 3e⁻ = N⁺² 5
P⁰ - 5e⁻ = P⁺⁵ 3
