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Paha777 [63]
3 years ago
5

Balance the following redox equation, identifying the element oxidized and the element reduced. Show all of the work used to sol

ve the problem.
HNO3 + P ---> H3PO4 + NO

Chemistry
2 answers:
Vlad1618 [11]3 years ago
7 0
5HNO₃ + 3P + 2H₂O = 3H₃PO₄ + 5NO

N⁺⁵ + 3e⁻ = N⁺²    5
P⁰ - 5e⁻ = P⁺⁵       3
forsale [732]3 years ago
4 0

<u>Answer:</u> Phosphorus is getting oxidized and nitrogen is getting reduced.

<u>Explanation:</u>

Oxidation reaction is defined as the reaction in which a substance looses its electron. The oxidation state of the substance gets increased.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

For the given chemical reaction:

HNO_3+P\rightarrow H_3PO_4+NO

<u>On reactant side:</u>

Oxidation state of Hydrogen = +1

Oxidation state of Phosphorus = 0

Oxidation state of Nitrogen = +5

Oxidation state of Oxygen = -2

<u>On product side:</u>

Oxidation state of Hydrogen = +1

Oxidation state of Phosphorus = +5

Oxidation state of Nitrogen = +2

Oxidation state of Oxygen = -2

As, the oxidation state of phosphorus is getting increased from 0 to +5, this is getting oxidized and the oxidation state of nitrogen is getting reduced from +5 to +2, this is getting reduced.

Hence, phosphorus is getting oxidized and nitrogen is getting reduced.

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What is the molarity of chloride ion in a solution made by dissolving 1.300g of aluminumchloride in a total volume of 500.0mL?
navik [9.2K]

Answer:

0.0582 M

Explanation:

The following data were obtained from the question:

Mass of AlCl3 = 1.3 g

Volume of water = 500 mL

Molarity of chloride ion (Cl¯) =?

Next, we shall determine the number of mole in 1.3 g of AlCl3. This can be obtained as follow:

Mass of AlCl3 = 1.3 g

Molar mass of AlCl3 = 27 + (35.5×3)

= 27 + 106.5

= 133.5 g/mol

Mole of AlCl3 =?

Mole = mass /molar mass

Mole of AlCl3 = 1.3/133.5

Mole of AlCl3 = 0.0097 mole

Next, we shall convert 500 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

500 mL = 0.5 L

Thus, 500 mL is equivalent to 0.5 L.

Next, we shall determine the molarity of the AlCl3 solution. This can be obtained as follow:

Mole of AlCl3 = 0.0097 mole

Volume of water = 0.5 L

Molarity of AlCl3 =?

Molarity = mole /Volume

Molarity of AlCl3 = 0.0097 / 0.5

Molarity of AlCl3 = 0.0194 M

Next, we shall write the dissociation equation of AlCl3 in solution. This is illustrated below:

AlCl3 (aq) —> Al³⁺ (aq) + 3Cl¯ (aq)

From the balanced equation above,

1 mole of AlCl3 produced 3 moles of Cl¯.

Finally, we shall determine the molarity of the chloride ion Cl¯ in the solution as follow:

From the balanced equation above,

1 mole of AlCl3 produced 3 moles of Cl¯.

Therefore, 0.0194 M AlCl3 will produce = 0.0194 × 3 = 0.0582 M Cl¯.

Thus, the molarity of the chloride ion, Cl¯ in the solution is 0.0582 M.

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3 years ago
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andrey2020 [161]

Answer: 13.31 moles.

Explanation: So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon.

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How is the atmosphere like an ocean
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 <span>The ocean is primarily a liquid and the atmosphere is mostly gas, so they are different states of matter. They also have different chemical compositions which really ought to be common knowledge. Also, very few fish swim in the sky.

YEP

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In the chemical laboratory, why do scientists use a mortar and pestle?
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