The final pressure of the gas in the container is 4 atm
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 300 K
Initial pressure (P₁) = 1 atm
Final temperature (T₂) = 600 K
Final volume (V₂) = 2 L
<h3>Final pressure (P₂) =?</h3>
- Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:
Cross multiply
300 × 2 × P₂ = 4 × 600
600 × P₂ = 2400
Divide both side by 600
<h3>P₂ = 4 atm</h3>
Therefore, the final pressure of gas is 4 atm.
Learn more: brainly.com/question/23558057
<span><span>1. </span><span>Fe2O3 or Iron (III)
oxide is an organic compound. It contains 3 main oxides of Iron, the iron (II)
oxide (FeO) and the iron (II, III) oxide (Fe3O4).
Now, let’s find the number of Molecules are there in 79g of Fe203:
The number of Atoms are there:
Molar Mass of Fe2O3 = 160g / mol.
=> 160g of Fe2O<span>3 </span>= 6.02 x 1023 Molecules
=> 79g of Fe2O3 = x
Next, find the value of X, in where:
x = (6.02 x 1023 x 79g) / 160g is approximately
x = 2.97 x 1023 molecules.</span></span>
Answer:
B
Explanation:
I had tried my best to get this answer and I had gotten B
sorry if it was not the right answer but I would recommend B
