The answer is b, chromatin
Answer:
26% is the percent of the population will have an A blood type (Option C)
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
Plant produces glucose in the chloroplast through the process of photosynthesis. Calvin cycle is basically the biological process through which glucose is produced. The steps involved are as follows:
1. Absorbed CO2 is added to RuBP and 6C sugar is formed.
2. Breaking of 6C sugar into two 3-phosphoglycerate molecules
3. ATP gives phosphate group to form 3-phosphoglycerate which is later on converted into 1,3-biphosphoglycerate.
4. Electons are required by 1,3-biphosphoglycerate to an aldehyde called glyceraldehyde-3-phosphate or G3P and these electrons are donated by NADPH
5. Enzyme aldolase uses two molecules of G3P to produce 6 C sugar called fructose-1,6-biphosphate which is further converted to fructose-6-phosphate
6. Enzyme isomerase converts fructose-6-phosphate to glucose-1-phosphate
Answer:
<h2>Recombination rate or recombination frequency between locus A and locus C is either 2% or 50%.
</h2>
Explanation:
As given,
Recombination frequency between locus A and B is 35%, means that the distance between A and B is 35 cM.
Recombination frequency between locus B and C is 33% , means the distance between B and C is 33 cM.
Therefore, if the locus C is present between A and B, then the recombination frequency between A and C would be 2%
A-----C ----------B
A---C= 2%
A----B= 35%
B---C= 33%
So, here the recombination frequency between A and C is 2%, means their distance is 2 cM.
If the locus C is as, A---35---B--33----C ; A-----B------C
A-----B= 35%
B------C= 33%
A-----C= 33+35= 68%
As rule, maximum frequency can not exceed 50%, as here the Recombination frequency between A and C = 50%.
Oxygen is the correct answer !