Answer:
The general plan is to find BM and from that CM. You need 2 equations to do that.
Step One
Set up the two equations.
(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32
BM^2 + CM^2 = 5^2 = 25
Step Two
Subtract the two equations.
(7 - BM)^2 + CM^2 = 32
BM^2 + CM^2 = 25
(7 - BM)^2 - BM^2 = 7 (3)
Step three
Expand the left side of the new equation labeled (3)
49 - 14BM + BM^2 - BM^2 = 7
Step 4
Simplify And Solve
49 - 14BM = 7 Subtract 49 from both sides.
-49 - 14BM = 7 - 49
- 14BM = - 42 Divide by - 14
BM = -42 / - 14
BM = 3
Step Five
Find CM
CM^2 + BM^2 = 5^2
CM^2 + 3^2 = 5^2 Subtract 3^2 from both sides.
CM^2 = 25 - 9
CM^2 = 16 Take the square root of both sides.
sqrt(CM^2) = sqrt(16)
CM = 4 < Answer
Step-by-step explanation:
A group of friends spent 1, 0, 2, 3, 4, 3, 6, 1, 0, 1, 2, and 2 hours online last night. What are the 1st and 3rd quartiles for
charle [14.2K]
1 and 3 i just did the math tell me if i’m wrong
Answer:
x > 5
Step-by-step explanation:
Given that:
= -2(3x + 2) > -8x + 6
(negative sign before bracket will alter the internal signs when multiplied by each term)
= -6x - 4 > -8x +6
Taking x terms on left side and other constants on right side
= -6x + 8x > 6 +4
Signs will be changer for transferred terms
= 2x > 10
By Dividing both sides 2 we get
=x > 10/2
= x >5
Answer:
75°
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 6 , then
sum = 180° × 4 = 720°
let x be the sixth angle, then sum and equate to 720°
150 + 100 + 80 + 165 + 150 + x = 720
645 + x = 720 ( subtract 645 from both sides )
x = 75
The sixth interior angle is 75°
