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horrorfan [7]
2 years ago
5

5. Geometry A rectangular vegetable garden has a length of 8 ft and a width of 5 ft. The width is increased by 2 ft. By how many

square feet does the area increase?​
Mathematics
1 answer:
Firlakuza [10]2 years ago
4 0
A rectangular garden has a length of 5ft and a width of 8 ft. The length is increased by 2 feet. By how many square feet does the area increase?

Step 1. Area of a rectangle is given as A=length * width

Step 2. Then, A1=5*8=40 square feet of original area of rectangular garden.

Step 3. Then, A2=(5+2)*8=56 square feet since the length is increased by 2. feet.

Step 4. Difference = A2 - A1 = 56 - 40 = 16 square feet.

Step 5. ANSWER: The area increased by 16 square feet.
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3 years ago
-4 ( -3 + 7v )= -7v + 33
PSYCHO15rus [73]

Answer:

v = -1

Step-by-step explanation:

-4 (-3 + 7v) = -7v + 33

12 -28v = -7v + 33

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5 0
1 year ago
Two six-sided number cubes are rolled. What is the probability that a product of 12 is rolled? Express your answer as a decimal.
Aleksandr-060686 [28]

Answer:

1/9

Or .11 repeating (~.11)

Step-by-step explanation:

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Now, let's analyze 12.

2 * 6,  

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7 0
3 years ago
The tile pattern below is made up of trapezoids and rhombuses. What is the area of each figure in the pattern?
shutvik [7]

The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

<h3>How to find the area of a trapezoid and rhombus?</h3>

The given pattern consists of rhombus and trapezoids

The formula for calculating the area of rhombus is expressed as:

A = pq/2

Area of trapezoid = 0.5(a+b)h

Given the following

height  = 2in

a = 2in

b = 3in

Ara of rhombus = 1(4)/2 = 2 square inches

Area of the trapezoid = 0.5(2+3) * 2

Area of the trapezoid  = 5 square inches

Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively

Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096

6 0
2 years ago
What is the solution of the system? Use the elimination method. {4x+2y=182x+3y=15 Enter your answer in the boxes.
Oxana [17]
\left \{ {{4x+2y=18(1)} \atop {2x+3y=15(2)}} \right.
Lets multiply equation (2) by -2 to get:
-4x-6y=-30

Now we can add equations (1) and (2) to eliminate x:
\left \{ {{4x+2y=18}+ \atop {-4x-6y=-30}} \right.
-4y=-12
y= \frac{-12}{-4}
y=3
Now that we know the value of y, we can replace it in equation (1) to get the value of x:
4x+2(3)=18
4x+6=18
4x=12
x= \frac{12}{3}
x=3

We can conclude that both x and y are equal to 3.
6 0
3 years ago
Read 2 more answers
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