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3 years ago

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A Ferris wheel has a diameter of 80 meters. They want to make circular sign all over the inside surface of the wheel." For this

word problem, do you have to find the area or the circumference?

1 answer:

Lesechka [4]3 years ago

4 0

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Lillie Manson paid for tuition at a summer school with an installment loan of $3,600 at 9% interest for 12 months. Her monthly p

gizmo_the_mogwai [7]

After 6 months, ammount left to pay = $1,840.34
On the seventh month, he payed of the debt with the interest (for one month).
Amount paid off at the seventh month = 1840.34(1 + 0.09/12) = 1840.34(1.0075) = 1854.14

Amount to have paid in the remaining 6 months = 314.83 x 6 = 1888.98
Amount saved = 1888.98 - 1854.14 = $34.84

7 0

3 years ago

The diagonals of a rectangle measures 18.2 inches. the width of the rectangle is 6.7 is 6.7 inches. find the length of the recta

trasher [3.6K]

The length of the rectangle is 16.9

8 0

3 years ago

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

3 years ago

Please help me answer this.

Mariulka [41]

Answer:

(a) 3

Step-by-step explanation:

Calculate the slope m of the line given using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0,3) and (x₂, y₂ ) = (3, 2)

m = $\frac{2-3}{3-0}$ = - $\frac{1}{3}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{1}{3} }$ = 3 → (a)

5 0

3 years ago

Find the value of H:

rewona [7]

Answer:

The value of H is 28.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(H-6)/(-7-(-5))

m=(H-6)/(-7+5)

-11=(H-6)/-2

-11(-2)=H-6

22=H-6

H=22+6

H=28

7 0

2 years ago