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olya-2409 [2.1K]
3 years ago
8

Rename 2/5 and 1/2 using the least common denominator

Mathematics
1 answer:
kozerog [31]3 years ago
3 0

the common denominator is 10 (between 5 and 2)

for each numerator:

we divide the common denominator with the denominator of each fraction and then multiply with the numerator of the fraction

first fraction's numerator:

10 (c.d.) : 5 (denominator) = 2

2 * 2 (numerator) = 4

second one:

10 (c.d.) : 2 (denominator) = 5

5 * 1 (numerator) = 5

The fractions are 4/10 and 5/10

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Solve for x. i'll give brainiest!
pogonyaev

Answer:

5

Step-by-step explanation:

x = 5

6 0
3 years ago
COMPLETING THE SQUARE<br> 2x^2 -4x+3=9<br><br><br><br> 2. QUADRATIC FORMULA<br> 2x^2+4x=0
jek_recluse [69]
X = 3 and x = -1 are the answers for both. They are exactly the same equation. 

FOR COMPLETING THE SQUARE
Make in terms of ()^2 which you can do by adding numbers to both sides. Eventually it will look like this:
(2x - 1)^2 - 7 = 0
Add to both sides, take a square root and then solve. 

USE THE QUADRATIC FORMULA
Be sure to solve for zero and be aware of negatives when plugging in. 
3 0
3 years ago
What is the least common multiple for 6 and 21?
Crank
3 is the least common multiple for 6 and 21
5 0
3 years ago
The function D(t)=18t2−130t gives the distance a car going a certain speed will skid in t seconds. Find the time it would take f
Assoli18 [71]

The time it will take for the car to skid for 150 feet is 8.23 seconds.

<h3>How to find the time the car will skid?</h3>

The function D(t) = 18t² − 130t gives the distance a car going a certain speed will skid in t seconds.

The time the it would take for the car to skid for 150 feet can be calculated as follows:

Therefore,

D(t) = 18t² - 130t

150 =  18t² - 130t

18t² - 130t - 150 = 0

divide by 3

9t² - 65t - 75 = 0

Hence,

t = 65 ± 5√277 / 18

t = 8.23425471586 or -1.01166666667

Hence,

t = 8.23 seconds.

Therefore, the time it will take for the car to skid for 150 feet is 8.23 seconds.

learn more on function here: brainly.com/question/13927655

#SPJ1

7 0
2 years ago
If the altitude of an isosceles right triangle has a length of x units, what is the length of one leg of the large right triangl
SVETLANKA909090 [29]

the picture in the attached figure

we know that

if ABC is an isosceles triangle

then

AB=BC

angle A=angle C=45 degrees

and

triangle ABD and triangle BDC also are isosceles triangles

AD=BD=x

DC=BD=x

the hypotenuse AC is equal to

AC=AD+DC\\ AC=x+x\\ AC=2x

To find the length AB applying the Pythagorean Theorem

AC^{2} =AB^{2} +BC^{2}

remember that AB=BC

AC^{2} =2AB^{2}

AC^{2} =2AB^{2}\\\\ AB=\frac{AC}{\sqrt{2}}\\\\ AB=\frac{2x}{\sqrt{2}}\\\\ AB=x\sqrt{2}

therefore

the answer is

the length of one leg of the large right triangle in terms of x is equal to x\sqrt{2}

3 0
4 years ago
Read 2 more answers
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