Answer:
Step-by-step explanation:
Given:
Center of circle is at (5, -4).
A point on the circle is 
Equation of a circle with center 
and radius 'r' is given as:
Here, 
Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:
Using distance formula for the points (5, -4) and (-3, 2), we get
Therefore, the equation of the circle is:
Now, rewriting it in the form asked in the question, we get
Answer:
Rays: A, B, C, D - 4 rays for each.
Line segments: AB, BD, DC, CA.
Answer:
5x + 4y + 12 = 0
Step-by-step explanation:
Start with the point-slope equation of a straight line: y - k = m(x - h):
Here we are given the point (h, k): (-8, 7) and the slope m = -5/4. Inserting this info into the equation give above, we get: y - 7 = (-5/4)(x + 8).
We must put this equation into "standard form" Ax + By + C = 0.
Multiply all three terms by 4 to remove fractions: 4y - 28 = -5(x + 8), or
4y - 28 + 5x + 40 = 0
Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.
F(x) = 3x^32 + 8x^2 -22x +43
The ends of all the polynomials with even degree behave like quadratic functions.
Given the the coefficient of x^32 is positive, the function opens upwards. Then the two ends go up.
