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3 years ago

Can anyone help with this?

Mathematics

2 answers:

bija089 [108]3 years ago

4 0

Answer:

5 times 2=10

1.5 times 3=4.5

8 times 1/2=4

Step-by-step explanation:

10/5=2

4.5/3=1.5

4/ 1/2 changes to 4 times 2=8

i hope this helps u

pls give a brainliest and a thx ;)

3241004551 [841]3 years ago

3 0

The answer to number one is 2

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(GIVING BRAINLIEST) A company rents out 11 food booths and 26 game booths at the county fair. The fee for a food booth is $50 pl

bogdanovich [222]

The answer is 2500+215d

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5 0

3 years ago

The measure of angle O is 7pi/4. The measure of its reference angle is _degree, and tan O is _?

Fofino [41]

Identities that come from sums, differences, multiples, and fractions of angles

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4 years ago

Read 2 more answers

Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition

vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) $\pi + (-\pi) = 0$

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

$1 - 2 = -1$

$5 - 5 = 0$

$\frac{1}{2} - \frac{1}{4} = \frac{1}{2}$

$4 - 2 = 2$

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

In the given options (a) to (d), only

$\pi + (-\pi) = 0$ is not close under addition because:

$\pi$ is irrational while $0$ is rational

In other words, they belong to different set

8 0

3 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

spin [16.1K]

The other endpoint is (1, -17).

The midpoint formula is:

$m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Using our midpoint and endpoint, we have:
$(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
\\
\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}
$

For the first equation (to find the x-coordinate) we will multiply both sides by 2:
$6\times2=\frac{11+x_2}{2}\times 2
\\
\\12=11+x_2$

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂

For the second equation (the y-coordinate) we multiply both sides by 2:
$-11\times2=\frac{-5+y_2}{2}\times 2
\\
\\-22=-5+y_2$

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂

This means that (x₂, y₂) is at (1, -17).

4 0

3 years ago

Solve the equation 4 sin (x +30°) = 2 for 0 < x < 365

tatuchka [14]

$4 \sin(x + 30) = 2 \\ \sin(x + 30 ) = \frac{2}{4} \\ \sin(x + 30) = \frac{1}{2} \\ \sin(x + 30) = \sin(30) \\ x + 30 = 30 \\ x = 30 - 30 \\ x = 0$

Hence, x = 0°, 180° and 360° Ans

3 0

3 years ago